Answer:
Correct answer: Two point of intersection and one touch point.
Step-by-step explanation:
Cartesian form of parabola is: y= a(x-1)² + 5 and point named A(2,4)
when we replace the coordinates of the point A in the formula we get
a = - 1 and parabola is y= - (x-1)² + 5 which means that it faces the opening downwards. The parabola touches the circle in vertex.
God is with you!!!
Mean:
E[Y] = E[3X₁ + X₂]
E[Y] = 3 E[X₁] + E[X₂]
E[Y] = 3µ + µ
E[Y] = 4µ
Variance:
Var[Y] = Var[3X₁ + X₂]
Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]
(the covariance is 0 since X₁ and X₂ are independent)
Var[Y] = 9 Var[X₁] + Var[X₂]
Var[Y] = 9σ² + σ²
Var[Y] = 10σ²
The answer to the variable b is 708.4
There are 5 pennies in a nickel, and 10 pennies in a dime. Now in $3.90 there are 390 pennies.
n = number of nickels in the pile
d = number of dimes in the pile
we know the pile has 55 coins, therefore whatever "n" and "d" are, we know that
n + d = 55.
now, "n" is how many nickel coins are there, how many pennies is it in total? well, 5 pennies to a nickel, for "n" nickels, will then be 5(n) or
5n.
and "d" is how many dime coins are there, so therefore in "d" coins, there are 10(d) pennies, or
10d.
we also know the total amount of pennies is 390, therefore
5n + 10d = 390.
![\bf \begin{cases} n+d=55\implies \boxed{n}=55-d\\ 5n+10d=390\\ -------------\\ 5\left(\boxed{55-d} \right)+10d=390 \end{cases} \\\\\\ 275-5d+10d=390\implies 5d=115\implies d=\cfrac{115}{5}\implies d=23](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0An%2Bd%3D55%5Cimplies%20%5Cboxed%7Bn%7D%3D55-d%5C%5C%0A5n%2B10d%3D390%5C%5C%0A-------------%5C%5C%0A5%5Cleft%28%5Cboxed%7B55-d%7D%20%20%5Cright%29%2B10d%3D390%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A275-5d%2B10d%3D390%5Cimplies%205d%3D115%5Cimplies%20d%3D%5Ccfrac%7B115%7D%7B5%7D%5Cimplies%20d%3D23)
how many nickel coins are there anyway? well, n = 55 - d.