The polynomial is not factorable, so use the quadratic formula.
y^2 + 8y + 19 = 0
x = (-b +- sqrt(b^2 - 4ac))/(2a)
x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)
x = (-8 +- sqrt(64 - 76))/2
x = (-8 +- sqrt(-12))/2
If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.
If you have learned imaginary/complex numbers, then we'll continue.
x = (-8 +- 2i sqrt(3))/2
x = -4 +- i sqrt(3)
16 because 2•0 is 0. 8-0 is 8 and 2(8) is 16
Answer:
- Two unique triangles possible
Step-by-step explanation:
Given two sides of 10 cm and one 40° angle
<u>If we use these, we'll get isosceles triangle with:</u>
1. Included 40° angle.
<u>Then the other angles will be same and measure:</u>
2. Adjacent 40° angle. Then one of the angles must be 40° angle as opposite of 10 cm sides.
<u>The remaining angle will measure:</u>
There no more unique triangles possible, so the answer is two.
