1st number = n
2nd number = n+1
3rd number = n+2
sum of the squares of 3 consecutive numbers is 116
n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116 Last option.
Answer:
Step-by-step explanation:
3c + 5w = 16
6c + 2w = 22
-6c - 10w = -32
6c + 2w = 22
-8w = -10
w = 10/8 = 5/4 = $1.25 per lb
3c + 5(1.25) = 16
3c + 6.25 = 16
3c = 9.75
c = $3.25 per lb
Answer:
Cost = RM 857143
Loss = RM 107143
Step-by-step explanation:
<u>Given:</u>
- Selling price SP = RM 750000
- Loss% = 12.5
- Cost price CP = x
<u>Cost price is found as:</u>
- SP = CP - 12.5%
- 750000 = x - 12.5%
- 750000= x*(100-12.5)/100
- 750000= 0.875x
- x= 750000/0.875
- x≈ RM 857143
<u>Loss is:</u>
- RM 857143 - 750000 = RM 107143
Answer:
the answer should be 152.6 ! just moving the decimal over to the left!!
Hello!
You can expand the 4
4x + 8
the answer is 4x + 8
Hope this helps!
