the system has no solution.
Option C is correct.
Step-by-step explanation:
We need to solve the system of equations by substitution

Putting value of x from eq(2) into eq(1)

As as 0≠4is not true, we cannot find the value of y so the system has no solution.
Option C is correct.
Keywords: System of equations
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Answer:
Yes
Step-by-step explanation:
A rectangle can be scaled into a square + rhombus. The difficult part is a trapezoid. If you can scale the sides, then the answer will remain yes because you would just make the top side longer both ways to straighten it and shorten the side lines.
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
Answer:(x,y)=(2.5,1)
Step-by-step explanation:
Given


thus on comparing
2x+y=6------1


On comparing exponent of 2
------2
we get x=2.5
substitute x in 1
y=1
(x,y)=(2.5,1)
Answer:
the answer is 3
Step-by-step explanation: