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MissTica
3 years ago
9

The graph of the equation y=f(x) passes through the points (-2,-5), (0,1), (1,4) and (2,7). What is the value of y in the equati

on y=f(1)?
Mathematics
1 answer:
aleksley [76]3 years ago
7 0

Answer: y=4

Step-by-step explanation:

There are different ways to solve this problem. One is to know how functions work, and the other is to create a function and plug in x=1. In this case, we are lucky that they gave us a point where x=1. The point is (1,4).

Knowing a function, you plug in an x and output a y. In the point (1,4), you are inputting 1 and outputting 4.

This is the same things as saying f(1)=y, or f(1)=4. Therefore, the value is y=4.

You might be interested in
X - y = 6
Dominik [7]

the system has no solution.

Option C is correct.

Step-by-step explanation:

We need to solve the system of equations by substitution

x - y = 6\,\,\,eq(1)\\x = y + 2\,\,\,eq(2)

Putting value of x from eq(2) into eq(1)

(y+2)-y=6\\y+2-y=6\\0+2=6\\0=6-2\\0\neq4

As as 0≠4is not true, we cannot find the value of y so the system has no solution.

Option C is correct.

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/7490805
  • brainly.com/question/9045597
  • brainly.com/question/13168205

#learnwithBrainly

4 0
3 years ago
Suppose Quadrilaterals A and B are both squares. Are A and B necessarily scaled
nevsk [136]

Answer:

Yes

Step-by-step explanation:

A rectangle can be scaled into a square + rhombus. The difficult part is a trapezoid. If you can scale the sides, then the answer will remain yes because you would just make the top side longer both ways to straighten it and shorten the side lines.

8 0
2 years ago
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
Solve the following systems of equations.<br> 2^(2x+y−1) = 32<br> 4^(x−2y) = 2
Rina8888 [55]

Answer:(x,y)=(2.5,1)

Step-by-step explanation:

Given

2^{2x+y-1}=32

2^{2x+y-1}=2^5

thus on comparing  

2x+y=6------1

4^{x-2y}=2

2^{2(x-2y)}=2

On comparing exponent of 2

x-2y=\frac{1}{2} ------2

we get x=2.5

substitute x in 1

y=1

(x,y)=(2.5,1)

6 0
3 years ago
I need help ASAP. This is multiple choice
kvv77 [185]

Answer:

the answer is 3

Step-by-step explanation:

7 0
3 years ago
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