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damaskus [11]
3 years ago
10

Help please,I dont know how do it!

Mathematics
1 answer:
nadezda [96]3 years ago
3 0
Use a formula given to you from there u will understand I am in 8th grade text me at 4042876133 for further help
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Find the ninth term of the sequence sqrt 5, sqrt 10, ^2sqrt 5
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The rule of geometric sequence is   ⇒⇒⇒ a * r^(n-1)
Where a is the first term and  r is the common ratio
for the given sequence  √5 , √10 , 2√5 , .......
a = √5
r = √10 / √5 = √2
The ninth term = √5 * (√2)^(9-1) = √5 * (√2)⁸ = 16 √5

the correct answer is the third option 16√5
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3x + 40 = 11x -24<br><br> What does x equal?
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First, you would have to do 11x + 3x Since you're combining like terms.

Now your problem is 14x + 40 = -24

Now you would do 40 - -24 which is now 40+24 and equal to 64.

Now you divide 14 by 64 and you get 4.5
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Answer:

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