All categories

2 years ago

For any value of x, the sum 3 ∑ k(2x-1) k=0 is equivalent to

Mathematics

1 answer:

MArishka [77]2 years ago

8 0

The equivalent value of the sum for any value of "x" is 12x - 6

<h3>How to find the sum of functions?</h3>

Given the sum of the expression as:

∑ k(2x-1)

k=0

We need to take the sum of the function at the point where k = 0 to 3

∑ k(2x-1) = 0(2x-1) + 1(2x - 1) + 2(2x-1) + 3(2x - 1)

k=0

∑ k(2x-1) = 2x-1+4x-2+6x-3

k=0

∑ k(2x-1) = 12x - 6

k=0

Hence the equivalent value of the sum for any value of "x" is 12x - 6

Learn more on sum functions here: brainly.com/question/24295771

You might be interested in

Please help me!!! what is the average of 24, 38, and 19?

faust18 [17]

You have to add up all the numbers then divide by the amount of numbers there are
24+38+19=81
81/3=27
The average is 27

6 0

2 years ago

Read 2 more answers

PLEASE HELP WILL GIVE BRAINLIEST NOW

hoa [83]

Answer:

5. (2,4) 6. (-1,6)

Step-by-step explanation:

The solution to multiple graphs is where the two graphs meet.

(-1,6) is the only point where both of the y values are the same.

7 0

2 years ago

Someone can help??

oee [108]

Answer:

Step-by-step explanation:

let cos^{-1}x=t

cos t=x

when x=1,cos t=1=cos 0

t \rightarrow 0

$\lim_{x \to 1} \frac{1-\sqrt{x}}{(cos ^{-1}x)^2 } \\= \lim_{t \to 0} \frac{1-\sqrt{cos~t}}{t^2} \times \frac{1+\sqrt{cos~t}}{1+\sqrt{cos ~t}} \\= \lim_{t \to 0} \frac{1-cos~t}{t^2(1+\sqrt{cos~t})}} \\= \lim_{t \to 0 }\frac{2 sin^2~\frac{t}{2}}{t^2(1+\sqrt{cos~t})}} \\= 2\lim_{t \to 0 }(\frac{sin~t/2}{\frac{t}{2} })^2 \times \frac{1}{4} \times \lim_{t \to 0 }\frac{1}{1+\sqrt{cos~t}} \\=\frac{2}4} \times 1^2 \times \frac{1}{1+\sqrt{cos~0}} \\=\frac{1}{2} \times \frac{1}{1+1} \\=\frac{1}{4}$

4 0

3 years ago

Marcy has 567 earmuffs in stock if she can put 18 earmuffs on each shelf, about how many shelves does she need for all of the ea

Nitella [24]

It would be: 567/18 = 31.5

So, she needs atleast 32 shelves....

8 0

3 years ago

Read 2 more answers

30 treadmills to 36 elliptical machines the ratio in simplest form

Goshia [24]

30 treadmills : 36 ellipticals
this could be written in a few ways, but i am going to write it as a fraction. since treadmills come first, you put 30/36.

now that you have your fraction you have to find the GCF (greatest common factor) of the two numbers. the GCF is 6, so you have to divide 30 treadmills by 6, and 36 ellipticals by 6.
30/6=5
36/6=6

5/6 or 5:6 is the simplified ratio of treadmills to ellipticals

comment for any questions!!

4 0

3 years ago