The regression equation which correctly models the data in this table is y = 1.49x - 107.5,
<h3>How to determine the regression equation?</h3>
From the table of data values, we have the following parameters:
∑x = 632
∑y = 404
∑x² = 80.142
∑xy = 51.448
Mathematically, the regression equation is represented by the following slope equation:
y = Bx + A
Next, we would determine A by using this expression:
A = (∑y·∑x² - ∑x·∑xy)/(n∑x² - (∑x)²)
A = (404×80,142 - 632×51,448)/(5×∑x² - (632)²)
A = (32,377,368 - 32,515136)/(5×80142 - 399,424)
A = -137,768/1286
A = 107.5
For B, we have:
B = (n∑xy· - ∑x·∑y)/(n∑x² - (∑x)²)
B = (5×51,448 - 632×404)/(5×∑x² - (632)²)
B = 1.49.
y = Bx + A
y = 1.49x - 107.5
Read more about regression equation here: brainly.com/question/28037520
#SPJ1
Answer:
15?
Step-by-step explanation:
Answer:
The fraction of the original strip left is
.
Step-by-step explanation:
We have that,
A strip of paper is cut in
. So, the strip of paper left is
.
Now, again the remaining part is cut in half. The part left will be
i.e.
.
Finally, the remaining part is again cut in half.
We get, the final part of the paper remaining is
i.e.
.
So, the fraction of the original strip left is
.
Answer:
4.5 per package
Step-by-step explanation:
Though they give us 4 different pairs of values on the table, we only need 1 pair to solve this question. For simplicity, lets chose the pair of whole numbers:
54 : 12
This is the ration of servings to packages, or the servings per package.
To get our answer, we must find how many servings per 1 package, so we need to divide by 12:

=
4.5 : 1
This means that there are 4.5 servings per 1 package!
Hope this helps!
check the picture below on the top side.
we know that x = 4 = b, therefore, using the 30-60-90 rule, h = 4√3, and DC = 4+8+4 = 16.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=8\\ b=\stackrel{DC}{16}\\ h=4\sqrt{3} \end{cases}\implies A=\cfrac{4\sqrt{3}(8+16)}{2} \\\\\\ A=2\sqrt{3}(24)\implies \boxed{A=48\sqrt{3}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%0A%5Cbegin%7Bcases%7D%0Aa%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D8%5C%5C%0Ab%3D%5Cstackrel%7BDC%7D%7B16%7D%5C%5C%0Ah%3D4%5Csqrt%7B3%7D%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B4%5Csqrt%7B3%7D%288%2B16%29%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D2%5Csqrt%7B3%7D%2824%29%5Cimplies%20%5Cboxed%7BA%3D48%5Csqrt%7B3%7D%7D)
now, check the picture below on the bottom side.
since we know x = 9, then b = 9, therefore DC = 9+6+9 = 24, and h = b = 9.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=\stackrel{DC}{24}\\ h=9 \end{cases}\implies A=\cfrac{9(6+24)}{2} \\\\\\ A=\cfrac{9(30)}{2}\implies \boxed{A=135}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%0A%5Cbegin%7Bcases%7D%0Aa%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D6%5C%5C%0Ab%3D%5Cstackrel%7BDC%7D%7B24%7D%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B9%286%2B24%29%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B9%2830%29%7D%7B2%7D%5Cimplies%20%5Cboxed%7BA%3D135%7D)