One can estimate the oil reservoir pressure underground from the height the oil rises. Of the gusher rises to 200 ft above groun
1 answer:
Answer:
12,608 kPa
Explanation:
First we need to convert the density to standard units, that is kg/m^3
0.85 g/cm^3 = 0.85 × = 0.85 × 1000 = 850 kg/m^3
Pressure of oil = pressure at surface + rho × g × h
= 101,000 + (850×9.81×1500)
= 12,608 kPa
The units in the part 'rho.g.h' will cancel out against each other and you will be left with the unit Pascals - which is the unit for pressure.
Hope that answers the question, have a great day!
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Explanation:
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Answer:
2000 W
Explanation:
First of all, we need to find the output voltage in the transformer, by using the transformer equation:
where here we have
V1 = 200 V is the voltage in the primary coil
V2 is the voltage in the secondary coil
N1 = 250 is the number of turns in the primary coil
N2 = 500 is the number of turns in the secondary coil
Solving for V2,
Now we can find the power output, which is given by
P = VI
where
V = 400 V is the output voltage
I = 5 A is the output current
Substituting,
P = (400 V)(5 A) = 2,000 W
Answer:
The magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.
Explanation:
Given;
number of turns of the flat circular loop, N = 18 turns
radius of the loop, R = 15.0 cm = 0.15 m
current through the wire, I = 0.51 A
The magnetic field through the center of the loop is given by;
Where;
μ₀ is permeability of free space = 4π x 10⁻⁷ m/A
Therefore, the magnitude of the magnetic field at the center of the loop is 3.846 x 10⁻⁵ T.