Question

One can estimate the oil reservoir pressure underground from the height the oil rises. Of the gusher rises to 200 ft above ground and the diameter of the bore pipe that goes down to the oil reservoir underground is 9 inches, calculate the oil pressure in a reservoir that is 1500 m below ground. The oil density is 0.85 g/cm3 and viscosity is 200 cP

Answer 1

Answer:

12,608 kPa

Explanation:

First we need to convert the density to standard units, that is kg/m^3

0.85 g/cm^3 = 0.85 × $\frac{100^{3} }{1000}$ = 0.85 × 1000 = 850 kg/m^3

Pressure of oil = pressure at surface + rho × g × h

= 101,000 + (850×9.81×1500)

= 12,608 kPa

The units in the part 'rho.g.h' will cancel out against each other and you will be left with the unit Pascals - which is the unit for pressure.

Hope that answers the question, have a great day!