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storchak [24]
2 years ago
10

if a mass on a spring bobs up nad down completing 2 full cycles every section. WHat are the periouds and frequency of the mass

Physics
1 answer:
Alika [10]2 years ago
4 0

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the time taken to complete one full cycle.

Frequency (<em>f</em>) will be calculated first as

<em>f </em>= <em>N </em>÷<em> t</em>

where <em>N </em>is the number of cycles and <em>t </em>is the time taken to complete one full cycle. The unit for frequency is Hertz (Hz).

To calculate the period, <em>T, </em>the formula below will be used

<em>T </em>= 1 ÷ <em>f</em>

The unit for period is secs

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A train moves with a constant velocity for 15s for 155m. How fast is the train moving?
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Explanation:

In theory and for a constant velocity the physics expression states that:

Eq(1):  distance  = velocity times time <=> d = v*t    for v=constant.

If we solve Eq (1) for the velocity (v) we obtain:

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Substituting the known values for t=15s and d=155m we get:

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5 0
3 years ago
A 1500 kg car traveling at 80.0 km/h comes to a screeching halt in a time of 4.00 seconds. Calculate the force of friction exper
amm1812

Answer:

F=m x a

(F is force ,M is mass and A is acceleration)

in thisncase the Mass is given but we need to find ou the acceleration

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a=(v - u)/t

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a = (0 - 80)/4

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7 0
3 years ago
If we start with 1.000 g of cobalt-60, 0.675 g will remain after 3.00 yr. this means that the of is _____
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<span>Cobalt-60 is undergoing a radioactivity decay.

The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span>           n </span>⇒ remaining mass of cobalt after 3 years
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So,
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t = 3÷0.567
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the half-life of Cobalt-60 is 5.29 years. 

<span>           
</span><span>
</span>
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