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storchak [24]
3 years ago
10

if a mass on a spring bobs up nad down completing 2 full cycles every section. WHat are the periouds and frequency of the mass

Physics
1 answer:
Alika [10]3 years ago
4 0

Answer:

This question is incomplete

Explanation:

This question is incomplete because of the absence of the time taken to complete one full cycle.

Frequency (<em>f</em>) will be calculated first as

<em>f </em>= <em>N </em>÷<em> t</em>

where <em>N </em>is the number of cycles and <em>t </em>is the time taken to complete one full cycle. The unit for frequency is Hertz (Hz).

To calculate the period, <em>T, </em>the formula below will be used

<em>T </em>= 1 ÷ <em>f</em>

The unit for period is secs

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What is the colour of third band of a coded resistor having resistance equal equal to 2.3*10`2
Helen [10]

Color of third band of a coded resistor is Brown.

What is Resistance:

  • Resistance is a measure of the opposition to current flow in an electrical circuit.
  • Resistance is measured in ohms, omega (Ω)

The color code specify the resistance value, the tolerance, and sometimes the reliability or failure rate.

How to identify resistor's color codes:

  1. Look at the resistor so the group of 3 or 4 color bands are on the left side
  2. Read the color bands from left to right.
  3. Read the color on the last color band, which is farthest right.
  4. compare the colors to the resistance code table

Here,

the value of resistance is 2.3x10^2 Ω

R = 23x10^1 Ω

here power of 10 is 1

so, the color of third band of a color coded resistor will be related to number 1

Hence,

color of third band of a coded resistor is Brown.

Learn more about resistor's color codes here:

<u>brainly.com/question/24359143</u>

<u />

#SPJ4

4 0
2 years ago
11) Arthur and Betty start walking toward each other when they are 100 m apart. Arthur has a speed of 3.0 m/s and Betty has a sp
sleet_krkn [62]

Answer:

100 m

Explanation:

Arthur and Betty should be walking the same amount of time if they start walking at the same time and stop when they meet = t

Speed of Arthur = 3 m/s

Speed of Betty = 2 m/s

Distance = Speed × time

Distance covered by Arthur = 3t

Distance covered by Betty = 2t

The distance covered by both of them will be 100 m

3t+2t=100\\\Rightarrow 5t=100\\\Rightarrow t=\frac{100}{5}\\\Rightarrow t=20\ s

The speed of dog is 5 m/s

Spot is running back and forth at 5 m/s for 20 seconds

In 20 seconds the distance covered by the dog is

\mathbf{5\times 20}=\mathbf{100\ m}

5 0
4 years ago
Calculate the efficiency of a machine if the input work is 200J and the output work is 150J.​
lidiya [134]

Answer:

75% is the efficency of this maxhine

8 0
3 years ago
A 238 N force is applied to a 25 kg object. What is the object's acceleration?
Ganezh [65]

Answer:

<h2>9.52 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{238}{25}  \\  = 9.52

We have the final answer as

<h3>9.52 m/s²</h3>

Hope this helps you

7 0
3 years ago
PE:
ella [17]

Answer:

The answers are:

T, T, F, F, T, T, F, F, T, T, F

Good luck!

7 0
3 years ago
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