1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SVEN [57.7K]
3 years ago
5

Mega rayquaza and zygarde 100% form vs lunala, solgaleo, and red's mega charizard

Physics
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

That right there is what caused the world to end my friend

Explanation:

You might be interested in
Consider massive gliders that slide friction-free along a horizontal air track. Glider A has a mass of 1 kg, a speed of 1 m/s, a
mamaluj [8]

Answer:

0.167m/s

Explanation:

According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.

Given momentum = Maas × velocity.

Momentum of glider A = 1kg×1m/s

Momentum of glider = 1kgm/s

Momentum of glider B = 5kg × 0m/s

The initial velocity of glider B is zero since it is at rest.

Momentum of glider B = 0kgm/s

Momentum of the bodies after collision = (mA+mB)v where;

mA and mB are the masses of the gliders

v is their common velocity after collision.

Momentum = (1+5)v

Momentum after collision = 6v

According to the law of conservation of momentum;

1kgm/s + 0kgm/s = 6v

1 =6v

V =1/6m/s

Their speed after collision will be 0.167m/s

6 0
3 years ago
A marble is dropped from rest and falls for 2.3 seconds. Find its final velocity.
juin [17]

Answer:

23 m/s downward

__________________________________________________________

<em>Taking the downward direction as positive</em>

<u>We are given:</u>

Initial velocity of the marble (u) = 0 m/s

Time interval (t) = 2.3 seconds

Final velocity (v) = x m/s

<u>Solving for the Final velocity:</u>

<u>Acceleration of the Marble:</u>

We know that gravity will make the marble accelerate at a constant acceleration of 10 m/s

<u>Final velocity:</u>

v = u + at                                              [First equation of motion]

x = 0 + (10)(2.3)                                    [replacing the given values]

x = 23 m/s

Hence, after 2.3 seconds, the marble will move at a velocity of 23 m/s in the downward direction

4 0
3 years ago
A portion of the atmosphere that becomes warmer than surrounding air will ____.
earnstyle [38]
<span>A portion of the atmosphere that becomes warmer than surrounding air will expand and rise. The warmer atmosphere the more space between the molecules. Therefore, warmer atmosphere </span><span>expands to allow more space for the molecules. Cool air on the other hand, contracts because the molecules in cool air need less space.</span>
3 0
3 years ago
How is color related to wavelength?
dlinn [17]
<span>Each color has a different wavelength allowing the eye to see it.</span>
8 0
3 years ago
A skydiver has a mass of 65 kg.<br> Calculate the weight of the skydiver.
Vinil7 [7]
F=m*a
F=65 kg *9.8 m/s^2
F=637 N (Newtons) — this is the weight
3 0
3 years ago
Other questions:
  • I need help fast!!!
    6·1 answer
  • Someone please help me!
    8·1 answer
  • What is the displacement of a spring if it has a spring constant of 10 N/m, and a force of 2.5 N is applied?
    6·2 answers
  • Objects falling through the air experience a type of friction called air resistance. true or false
    8·2 answers
  • What are the three reasons why nebula contribute more to Stellar formation than any other region in the universe?
    15·2 answers
  • Need help on this thanks<br>​
    7·1 answer
  • Why is the sky blue? The earth is surrounded by an atmosphere.
    12·1 answer
  • Problem 18 if anyone could help that would be amazing!
    8·1 answer
  • What is a magnetic flux thru closed surface
    6·1 answer
  • Elements in the periodic table are arranged in order of increasing...
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!