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tester [92]
3 years ago
10

EXPLAIN THE PROCESS OF SEPERATING A MIXTURE CONSISTING OF IRON fillings and sand in a plastic bowl

Chemistry
1 answer:
devlian [24]3 years ago
5 0
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ Iron would be attracted to a magnet therefore, you can hover a magnet over the mixture. Doing this would lift out the iron fillings, leaving the sand behind.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

You might be interested in
Compounds Lab Report
lukranit [14]

Name and Title:

Colleen DeBruin, Hillary Mulkavits, 11/18/2020, compounds lab.

Objectives(s):

to build chemical compounds from known elements

Hypothesis:

if I use oxygen hydrogen and carbon then I can make five new compounds in four minutes

Procedure:

The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome. Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.

Data:

Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.

Compound Name Chemical Formula Sodium (Na) Atoms Calcium (Ca) Atoms Hydrogen (H) Atoms Oxygen (O) Atoms Carbon (C) Atoms Chlorine (Cl) Atoms

Ex: Sodium

hypochlorite NaClO 1 0 0 1 0 1

Water H20 o 0 1 2 0 0

Glucose C6H12O6 0 0 12 6 6 0

Formic/methanoic acid HCOOH 0 0 2 2 1 0

Butanoic Acid C3H7COOH 0 0 8 2 4 0

Carbon Dioxide C02 0 0 0 2 1 0

Carbon Monoxide CO 0 0 0 1 1 0

Fructose C6H12O6 0 0 12 6 6 0

0 0 0

0 0 0

0 0 0

Conclusion:

Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

I found as many combinations of carbon hydrogen and oxygen as possible

If there is a job that combines elements you would be doing that every day making it an every day matter

elements are like people, they are all different causing them to react differently and be more reactive

H20 has four because there are 2 oxygen and one hydrogen because of the numbers in the name of the compound

Yes because two elements can form two different types of bonds causing different outcomes

If this isn't right I'm sorry but I had it as an assignment so we will get it wrong together lol

8 0
3 years ago
Read 2 more answers
_______ are the smallest units of life.
anygoal [31]

Answer:

A.Cells

Explanation:

bugs eggs and bones aren't the smaller than cells.

5 0
3 years ago
Read 2 more answers
A 100mL reaction vessel initially contains 2.60x10^-2 moles of NO and 1.30x10^-2 moles of H2. At equilibrium the concentration o
Tcecarenko [31]

Answer:

Kc=17.7

Explanation:

Hello,

In this case, for the given reaction:

2H_2(g) + 2NO(g)\rightleftharpoons 2 H_2O(g) + N_2(g)

In such a way, the initial concentrations are:

[H_2]_0=\frac{1.30x10^{-2}mol}{0.1L}=0.130M

[NO]_0=\frac{2.60x10^{-2}mol}{0.1L}=0.260M

Thus, at equilibrium, the change x, due to the chemical reaction extent, turns out:

x=\frac{[NO]_{0}-[NO]_{eq}}{2} =\frac{0.260M-0.161M}{2}=0.049M

Thus, the rest of the concentrations at equilibrium are:

[H_2]_{eq}=0.130M-2(0.049M)=0.032M

[H_2O]_{eq}=2(0.049M)=0.098M

[N_2]_{eq}=0.049M

In such a way, the equilibrium constant for the reaction, result as follows, even when on the statement the NO is excluded, because it participates in the equilibrium:

Kc=\frac{[H_2O]_{eq}^2[N_2]_{eq}}{[H_2]_{eq}^2[NO]_{eq}^2}=\frac{(0.098M)^2(0.049M)}{(0.032M)^2(0.161M)^2} \\\\Kc=17.7

Best regards.

4 0
3 years ago
The specific type of bond that results from unequal sharing of electrons in the bond is
Damm [24]

Answer:

It's called A polar covalent bond

3 0
3 years ago
Caffeine has the molecular formula, C8H10N4O2. What is the percent composition of caffeine?
Paul [167]

Answer:

b) 49.48% C, 5.19% H, 28.85% N, and 16.48% O

Explanation:

According to this question, caffeine has a molecular formula of C8H10N4O2. In order to find the percentage composition of each element in this compound, we must first find the molar mass of the compound:

C8H10N4O2

Where; C = 12, H = 1, N = 14, O = 16

12(8) + 1(10) + 14(4) + 16(2)

96 + 10 + 56 + 32

194g/mol

Next, we find the percent composition of each element as follows by dividing mass of each element by molar mass of the compound and multiplying by 100

C = 96/194 × 100 = 49.48%

H = 10/194 × 100 = 5.15%

N = 56/194 × 100 = 28.86%

O = 32/194 × 100 = 16.49%

6 0
3 years ago
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