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tester [92]
3 years ago
10

EXPLAIN THE PROCESS OF SEPERATING A MIXTURE CONSISTING OF IRON fillings and sand in a plastic bowl

Chemistry
1 answer:
devlian [24]3 years ago
5 0
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ Iron would be attracted to a magnet therefore, you can hover a magnet over the mixture. Doing this would lift out the iron fillings, leaving the sand behind.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Organic compounds are distinguished by molecules that contain ________ bonded to other elements.
fredd [130]
The answer is carbon
6 0
3 years ago
Examples of physical and chemical weathering
lorasvet [3.4K]
Mass is always conserved in a physical change. Energy may be released or absorbed when a substance changes from one physical state to another. In a chemical change, a chemical reaction yields a completely new substance. A substance's particles are changed during a chemical reaction.
5 0
4 years ago
1. Which is a substance that cannot be broken down into another substance?
grandymaker [24]

Answer:

Atom

Explanation:

my theory:

Atoms are their own substance. It's atom because if you tried to break an atom, you would be going into nuclear physics. That would be unsafe and dangerous.

3 0
3 years ago
HCl is added to a solution containing barium and calcium ions. If a precipitate is formed, what is it? A. No precipitate is form
lord [1]

Answer:

A. No precipitate is formed

Explanation:

Hello,

In this case, since the reactions are:

Ca^{2+}(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H^+(aq)\\\\Ba^{2+}(aq)+2HCl(aq)\rightarrow BaCl_2(aq)+2H^+(aq)

We evidence no formation of insoluble salts or precipitates since both calcium and barium chlorides are largely soluble in water due to the ionic bond which binds them, thus A. No precipitate is formed.

Regards.

7 0
3 years ago
Find the volume of hydrogen gas formed when 1.5g of aluminum reacts with aq NaOH at 27 degrees Celcius.
Rudiy27

Answer:

how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?

(A) n=m/M,

n(Al)=5.4/27=0.2 moles

n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles

Number of oxygen atoms= n(O2)*Avogadro's number

=0.15*6.02*10^23=9.03*10^22 oxgyen atoms

(B)

n=m/M

n(Al)=0.6/27=0.02222 moles

n(O2)=n(Al)*3/4=0.016666 moles

m=n*M

m(O2)=0.0166666*32=0.53333 grams

8 0
2 years ago
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