Answer:
About 1.48 M.
Explanation:
The formula for molarity is mol/L.
So firstly, you must find the amount of moles in 250 grams of NaCl.
I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.
I get that 250 grams of NaCl is equal to about 4.28 moles.
Now I just plug into the formula!
4.28 moles/2.9 L = about 1.48
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Answer:
ΔH° = 840 kJ/mol
Explanation:
Let's consider the following balanced reaction:
2 AgNO₃(aq) + CaCl₂(aq) ⇄ 2 AgCl(s) + Ca(NO₃)₂
Then, we need to know the moles of both reactants:
AgNO₃: n = 0.200 mol/L × 0.0500 L = 0.0100 mol
CaCl₂: n = 0.100 mol/L × 0.0500 L = 0.00500 mol
According to the balanced equation we need 2 moles of AgNO₃ per each mole of CaCl₂, and this coincides with the experimental data, so there is no limiting reactant. Let's use AgNO₃ to find out how many moles of AgCl are produced.
Now, we can calculate the total amount of heat released using the following expression:
Q = c × m × ΔT
where,
c is the heat capacity of the solution
m is the mass of the solution
ΔT is the change in temperature (26.0 °C - 25.0°C = 1.00 °C)
Since the volume is 100.0 mL (50.0 mL + 50.0 mL) and the density is 1.05 g/mL, we can calculate the mass of the solution like:
m = 1.05 g/mL × 100.0 mL = 105 g
Then,
Finally,
The answer is letter a. Hill terrain, hill slope, and hill elevation
When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.
Noble gases
also known as Inert gases