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Xelga [282]
3 years ago
11

Compounds Lab Report

Chemistry
2 answers:
lukranit [14]3 years ago
8 0

Name and Title:

Colleen DeBruin, Hillary Mulkavits, 11/18/2020, compounds lab.

Objectives(s):

to build chemical compounds from known elements

Hypothesis:

if I use oxygen hydrogen and carbon then I can make five new compounds in four minutes

Procedure:

The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome. Using your summary questions at the end of your virtual lab activity, please clearly define the dependent and independent variables of the experiment.

Data:

Record the composition of each of your compounds below. Be sure to include the number of atoms for each element. An example has been supplied for you.

Compound Name Chemical Formula Sodium (Na) Atoms Calcium (Ca) Atoms Hydrogen (H) Atoms Oxygen (O) Atoms Carbon (C) Atoms Chlorine (Cl) Atoms

Ex: Sodium

hypochlorite NaClO 1 0 0 1 0 1

Water H20 o 0 1 2 0 0

Glucose C6H12O6 0 0 12 6 6 0

Formic/methanoic acid HCOOH 0 0 2 2 1 0

Butanoic Acid C3H7COOH 0 0 8 2 4 0

Carbon Dioxide C02 0 0 0 2 1 0

Carbon Monoxide CO 0 0 0 1 1 0

Fructose C6H12O6 0 0 12 6 6 0

0 0 0

0 0 0

0 0 0

Conclusion:

Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

I found as many combinations of carbon hydrogen and oxygen as possible

If there is a job that combines elements you would be doing that every day making it an every day matter

elements are like people, they are all different causing them to react differently and be more reactive

H20 has four because there are 2 oxygen and one hydrogen because of the numbers in the name of the compound

Yes because two elements can form two different types of bonds causing different outcomes

If this isn't right I'm sorry but I had it as an assignment so we will get it wrong together lol

FromTheMoon [43]3 years ago
8 0

Answer:

i hope this helps :)

Explanation:

its in the file

Download docx
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Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bo
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Complete Question

The complete question is shown on the first uploaded image

Answer:

X  is Be

Y  is B

Z  is  O            

Explanation:

In order to understand the solution, we need to that the an element form a bond based on

1  The number of valence electron available in its atom

2 The  number of electron it require to attains its stable state i.e its Octet  state

        The number of valence electron for each of the option  are

                 F = 7,   N = 5 , O = 6 , C = 4 , B = 3 , Be = 2

 Considering the first element

           We see that  X is donating  two valence electron in its atom and it is donating it to 2  Cl as Cl  only requires a single electron to achieve its stable state

Now looking  option we can see that  Be has two valence  electron in it atom and in order for it to attain its stable state it needs to release the electron so the correct option for this question is Be

Considering the second  element              

      We see that  Y is donating  three valence electron in its atom and it is donating it to 3  Cl as Cl  only requires a single electron to achieve its stable state    

    Now looking  option we can see that  B has three valence  electron in it atom and in order for it to attain its stable state it needs to release the valence electron so the correct option for this question is B

Considering the second  element  

      We see that  Z is donating two valence electron in its atom and it is donating it to 2  Cl as Cl  only requires a single electron to achieve its stable state, also Z has 2 lone-pair valence electron

       Now looking at the option we can see that  O has 6 valence electron so if it donates 2 valence electron it will still be left with 4 - pair of electron

   Therefore the correct option to this question is  O                  

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3 years ago
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levacccp [35]

Answer:

Two Half-lives

Explanation:

Let number of Parent nuclei Initially present be X,

Then, finally \frac{X}{4} Parent nuclei Will remain with \frac{3X}{4} daughter nuclei.

In one half- life , parent nuclei becomes half of initial.

So, starting with X parent nuclei,

After one half-life, it will degrade to \frac{X}{2} .

After another half life , Parent nuclei will become half of \frac{X}{2}

Which is equal to \frac{X}{4}.

So, Parent nuclei have to go through Two half-lives.

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