A student needed to dissolve a substance that she knew was soluble in water. according to the chart, which other solvent would m
ost likely dissolve the substance?
1 answer:
The chart is attached below and the options are as follow,
A Benzene
B Methanol
C Hexane
D Octane
Answer:
Option-B (Methanol) is the correct answer.
Explanation:
As we know that the substance given to student is soluble in water. Therefore, those substances which are soluble in water are polar in nature because water is polar in nature and Like Dissolves Like.
Hence, in chart it can easily be seen that Methanol is also polar in nature due to presence of -O-H (polar) bond. So, the substance will dissolve in it.
A Benzene
B Methanol
C Hexane
D Octane
Answer:
Option-B (Methanol) is the correct answer.
Explanation:
As we know that the substance given to student is soluble in water. Therefore, those substances which are soluble in water are polar in nature because water is polar in nature and Like Dissolves Like.
Hence, in chart it can easily be seen that Methanol is also polar in nature due to presence of -O-H (polar) bond. So, the substance will dissolve in it.
You might be interested in
Answer:
a)
b)
c)
Explanation:
a)
when is added to LiOH, lithium chlorate and water is formed.
Balancing of above reaction,
It can be seen that all the atoms in both the sides are balanced. so it is a balanced reaction.
(b) When aqueous is added to NaOH,
and
is formed. It is a neutrilization reaction.
Balancing of above reaction,
First balance all the atoms except O and H
S atom is already balanced in either side
No. of Na atom in left hand side = 1
No. of Na atom in right hand side = 2
So multiply NaOH by 2, now the reaction becomes:
No. of O atoms in left hand side = 6
No. of O atoms in right hand side = 5
So multiply H2O by 2, now the reaction becomes:
Now, it can been seen that all the atoms are balanced.
c) When reacts with HF, baroum fluoride and water is formed.
Balancing of above reaction,
Barium atoms are already balanced on either side.
No. of F atoms on left hand side = 1
No. of F atoms on right hand side = 2
So, multiply HF by 2, now reaction becomes
In order to balance H and O on either side, multiply H2O by 2.
Answer:
5.90, 11.8, 47.2
Explanation:
Let’s remove the parentheses and write the formula as MgCl₂O₈.
We see that 1 mol Mg(ClO₄)₂ contains 1 mol Mg atoms, 2 mol Cl atoms, and 8 mol O atoms.
∴
∴ Mg, Cl, O = 5.90, 11.8, 47.2