Answer:
Final temperature: 659.8ºC
Expansion work: 3*75=225 kJ
Internal energy change: 275 kJ
Explanation:
First, considering both initial and final states, write the energy balance:
Q is the only variable known. To determine the work, it is possible to consider the reversible process; the work done on a expansion reversible process may be calculated as:
The pressure is constant, so: 
(There is a multiplication by 100 due to the conversion of bar to kPa)
So, the internal energy change may be calculated from the energy balance (don't forget to multiply by the mass):
On the other hand, due to the low pressure the ideal gas law may be appropriate. The ideal gas law is written for both states:
Subtracting the first from the second:
Isolating 
:
Assuming that it is water steam, n=0.1666 kmol
ºC
There is fr-218
hope this did the job, have a nice rest of your day!!
Answer:
64g of Oxygen
Explanation:
Firstly, carbon and oxygen react to form CO2 as follows;
C + O2 => CO2
According to the equation, one mole of C reacts with one mole of O2 to give one mole of CO2
Since molar mass of C= 12g/mol, O= 16g/mol
One mole of (C) contains 12g
One mole of O2 contains 16(2) = 32g
Hence, If there are 24g of C, there would be 24 × 32 / 12
= 768/12
= 64g
Hence, there would be 64g of oxygen if there are 24g of Carbon
The reaction is:
2 KClO3(s) → 3 O2(g) + 2 KCl(s) <span>
<span>A catalyst simply lowers the activation energy so MnO2 is not
part of the overall reaction.
By stoichiometry:
<span>3.45 g KClO3 x 1 mol/ 122.55g KClO3 x 3 mol O2/ 2 mol KClO3 x
31.99g/ 1 mol O2 = 331.096/ 245.1 = 1.35 grams O2 produced
Answer:1.35 grams O2</span></span></span>
