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3 years ago

Please help! posted picture of question

Mathematics

1 answer:

Olin [163]3 years ago

7 0

A One-to-One function has only one value of y for a given value of x. Neither x value is paired with more than 1 y value, nor a y value is paired with more than 1 x values.

From the given options, the option A represents a One-to-One function.
In option B, a same y value occurs at more than one values of x. Same can be seen in option C. Therefore, these two are not One-to-One functions.

So, the correct answer is option A.

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Math Question. I need help. Please help me.

Yakvenalex [24]

Answer:

B = 3

Step-by-step explanation:

4+2b = 10

= 2b = 10-4

2b = 6

b = 6/2

= 3

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2 years ago

Read 2 more answers

Darla found that the least common denominator needed to subtract \frac{x}{x^2+4x-12}-\frac{3}{x+6}is (x + 6)(x – 2). Which is th

Leona [35]

<h3>Answer: Choice B</h3>

$\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}$

which is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

=====================================

Explanation:

The LCD is (x+6)(x-2) which is the factorization of x^2+4x-12, and that is the denominator of the first fraction. The first fraction has the LCD already. The second fraction does not. It has (x+6) but it is missing (x-2).

We multiply top and bottom of the second fraction by (x-2) to get the second fraction to have the LCD.

$\frac{3}{x+6}$ turns into $\frac{3}{x+6}*\frac{x-2}{x-2} = \frac{3(x-2)}{(x+6)(x-2)}$

------

So,

$\frac{x}{x^2+4x-12} - \frac{3}{x+6}$

$\frac{x}{(x+6)(x-2)} - \frac{3}{x+6}$

$\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}$

This is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

Note the parenthesis around "(x+6)(x-2)"

Instead of x/(x+6)(x-2) you should write x/( (x+6)(x-2) ) to ensure that all of "(x+6)(x-2)" is in the denominator.

4 0

3 years ago

WILL GIVE BRAINLIEST!! What is the y-intercept of a line that has a slope of 3 and passes through point (4, 8)?

mr_godi [17]

Answer:

-4

Step-by-step explanation:

If we set up the equation with the known info, we get y=3x+b

We can then use the ordered pair to plug in, so 8=12+b

Now, simply solve for B, and you get -4

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3 years ago

Which of the following can be added without altering any of the fractions?

S_A_V [24]

Answer:

Step-by-step explanation:

$\frac{3x}{x-1}$ + $\frac{8}{x-1}$

These fractions have a common denominator and so do not require to be altered.

The numerators can be added to simplify, that is

= $\frac{3x+8}{x-1}$

The remaining fractions have different denominators and would require to be altered before they could be added.

4 0

3 years ago

Use the table to identify the values of pand q that should be used to factor x2

lianna [129]

Answer:

p = -5 and q = 2 or p = 2 and q = -5

Step-by-step explanation:

Technically, you don't need the table to help you out here. If you solely just factor out x²-3x-10, you would get (x-5)(x+2). So one variable would always have to be -5 and the other variable would always have to be 2.

5 0

3 years ago