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3 years ago

Which of the following is not an example of an electrolytic solution? a sports drink sweat ocean water pure water

Chemistry

1 answer:

zzz [600]3 years ago

7 0

Answer: Option (d) is the correct answer.

Explanation:

An electrolytic solution which is conductive in nature, that is, a solution that has ions or atoms.

In the given options, sports drink, sweat, and ocean water are all electrolytic solution.

Whereas pure water has pH equals to 7, that is, pure water is neutral. Thus, we can conclude that pure water is not an example of an electrolytic solution.

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PLZZZZZ HELP MEEEEEE

Masja [62]

Answer:

0.0745 mole of hydrogen gas

Explanation:

Given parameters:

Number of H₂SO₄ = 0.0745 moles

Number of moles of Li = 1.5107 moles

Unknown:

Number of moles of H₂ produced = ?

Solution:

To solve this problem, we have to work from the known specie to the unknown one.

The known specie in this expression is the sulfuric acid, H₂SO₄. We can compare its number of moles with that of the unknown using a balanced chemical equation.

Balanced chemical equation:

2Li + H₂SO₄ → Li₂SO₄ + H₂

From the balanced equation;

Before proceeding, we need to obtain the limiting reagent. This is the reagent whose given proportion is in short supply. It determines the extent of the reaction.

2 mole of Li reacted with 1 mole of H₂SO₄

1.5107 mole of lithium will react with $\frac{1.5107}{2}$ = 0.7554mole of H₂SO₄

But we were given 0.0745 moles,

This suggests that the limiting reagent is the sulfuric acid because it is in short supply;

since 1 mole of sulfuric acid produced 1 mole of hydrogen gas;

0.0745 mole of sulfuric acid will produce 0.0745 mole of hydrogen gas

4 0

3 years ago

10. A 2.36-gram sample of NaHCO3 was completely decomposed in an

Airida [17]

Answer:

0.79 g

Explanation:

Let's introduce a strategy needed to solve any similar problem like this:

Apply the mass conservation law (assuming that this reaction goes 100 % to completion): the total mass of the reactants should be equal to the total mass of the products.

Based on the mass conservation law, we need to identify the reactants first. Our only reactant is sodium bicarbonate, so the total mass of the reactants is:

$m_r=m_{NaHCO_3}=2.36 g$

We have two products formed, sodium carbonate and carbonic acid. This implies that the total mass of the products is:

$m_p=m_{Na_2CO_3}+m_{H_2CO_3}$

Apply the law of mass conservation:

$m_r=m_p$

Substitute the given variables:

$m_{NaHCO_3}=m_{Na_2CO_3}+m_{H_2CO_3}$

Rearrange for the mass of carbonic acid:

$m_{H_2CO_3}=m_{NaHCO_3}-m_{Na_2CO_3}=2.36 g - 1.57 g=0.79 g$

8 0

4 years ago

5. How many molecules are in 0.550 moles of N2O5?

Mandarinka [93]

2.41 molecules, should be it

8 0

3 years ago

You wish to make 250. mL of 0.20 M KCl from a stock solution of 1.5 M KCl and DI water.

Nitella [24]

The question requires us to use the dilution formula $M_iV_i=M_fV_f$ , where $M_i$ and $V_i$ are the stock concentration and volume respectively, then $M_f$ and $V_f$ are the dilute concentration and volume respectively.