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3 years ago

5

Please help me this brought my grade down and I need to get it up by next week please please help im giving all my points away f

or it

1 answer:

sergiy2304 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

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After paying nine dollars for the pie , Sara has fifty-seven dollars left. How much money did she have before buying the pie ?

iren [92.7K]

Sara had $66.00 dollars before she bought the pie.

6 0

3 years ago

Find the slope of the line through the given points. d (3, 7) and (3, −8)

Romashka [77]

Answer:

Undefined

Step-by-step explanation:

Use rise over run (y2 - y1) / (x2 - x1), where (x1, y1) and (y1, y2) are points on the line

Plug in the given points:

(y2 - y1) / (x2 - x1)

(-8 - 7) / (3 - 3)

-15/0

= undefined

The slope is undefined, because you cannot divide by 0.

6 0

3 years ago

A solid right pyramid has a square base. The length of the base edge is4 cm and the height of the pyramid is 3 cm period what is

Illusion [34]

Answer:

The volume of this pyramid is 16 cm³.

Step-by-step explanation:

The volume $V$ of a solid pyramid can be given as:

$\displaystyle V = \frac{1}{3} \cdot b \cdot h$ ,

where

$b$ is the area of the base of the pyramid, and
$h$ is the height of the pyramid.

Here's how to solve this problem with calculus without using the previous formula.

Imaging cutting the square-base pyramid in half, horizontally. Each horizontal cross-section will be a square. The lengths of these squares' sides range from 0 cm to 3 cm. This length will be also be proportional to the vertical distance from the vertice of the pyramid.

Refer to the sketch attached. Let the vertical distance from the vertice be $x$ cm.

At the vertice of this pyramid, $x = 0$ and the length of a side of the square is also $0$ .
At the base of this pyramid, $x = 3$ and the length of a side of the square is $4$ cm.

As a result, the length of a side of the square will be

$\displaystyle \frac{x}{3}\times 4 = \frac{4}{3}x$ .

The area of the square will be

$\displaystyle \left(\frac{4}{3}x\right)^{2} = \frac{16}{9}x^{2}$ .

Integrate the area of the horizontal cross-section with respect to $x$

from the top of the pyramid, where $x = 0$ ,
to the base, where $x = 3$ .

$\displaystyle \begin{aligned}\int_{0}^{3}{\frac{16}{9}x^{2}\cdot dx} &= \frac{16}{9}\int_{0}^{3}{x^{2}\cdot dx}\\ &= \frac{16}{9}\cdot \left(\frac{1}{3}\int_{0}^{3}{3x^{2}\cdot dx}\right) & \text{Set up the integrand for power rule}\\ &= \left.\frac{16}{9}\times \frac{1}{3}\cdot x^{3}\right|^{3}_{0}\\ &= \frac{16}{27}\times 3^{3} \\ &= 16\end{aligned}$ .

In other words, the volume of this pyramid is 16 cubic centimeters.

5 0

3 years ago

Dominic observes the number of birds that come to the feeder each day for a

olchik [2.2K]

I think it would be 55

4 0

2 years ago

Please help me idk this

KiRa [710]

Answer:

$x=128$

Step-by-step explanation:

x and 52 are supplementary, so they add up to 180°

$x+52=180\\x=128$

6 0

3 years ago

Read 2 more answers