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Wewaii [24]
3 years ago
14

Use the graph of y=e^x to evaluate the expression e^-2.8 round the solution to the nearest tenth if necessary

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0
In this item, I assume that the variable "e" here stands for the Euler number which is equal to 2.718. Raising this number to the exponent -2.8 will give us an answer of, 
                                    y = e^-2.8 = (2.718)^-2.8 = 0.0608
Therefore, the value of y is approximately 0.1. 
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Can someone help me on this​
Strike441 [17]

Answer:

JK+KL=JL

Step-by-step explanation:

  • (x-6) +(2x-8) =16
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  • x+2x=16+6+8
  • 3x=30
  • x=30/3
  • x=10
  1. Now KL
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  • 2x10-8
  • 20-8
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6 0
3 years ago
Find the measure of angle z in the following figure
Pachacha [2.7K]

Answer:

z=40 degrees

Step-by-step explanation:

a triangle is 180 degrees

<ACB=50 (180-130=50)

50+90=140

180-140=40

8 0
3 years ago
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Select the comparison that is correct. (2 are right) A eighty-one tenths &gt; 8.27 B Six and seventy-nine thousandths 50.453 D 3
madreJ [45]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
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Simplify using the vertical method. (3k + 4)(3k^2 – 5k – 3)
liubo4ka [24]

Answer:

9k^{3} -3k^{2}-29k-12

Step-by-step explanation:

Step 1: Expand by distributing sum groups.

3k(3k^{2} -5k-3)+4(3k^{2} -5k-3)

Step 2: Expand by distributing terms.

9k^{3} -15k^{2} -9k+4(3k^{2} -5k-3)

Step 3: Expand by distributing terms.

9k^{3}-15k^{2} -9k+12k^{2} -20k-12

Step 4: Collect like terms.

9k^{3}+(-15k^{2}  +12k^{2} )+(-9k-20k)-12

Step 5: Simplify.

9k^{3} -3k^{2}-29k-12

3 0
3 years ago
A study of commuting times reports the travel times to work of a random sample of 1010 employed adults in Chicago. The mean is x
MrMuchimi

Answer:

standard error of the mean = 1.6960

Step-by-step explanation:

Given -

Mean (\overline{X}) = 53 minutes

Standard deviation ( s ) = 53.9 minutes

n = 1010

standard error of the mean  =  

\sigma _{\overline{X}}    =   \frac{s}{\sqrt{n}}

        = \frac{53.9}{\sqrt{1010}}

       =  1.6960

3 0
3 years ago
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