The slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Given that the points through which the line passes is (19,-16) and (-7,-15).
We are required to find the slope of the line which passes through (19,-16) and (-7,-15).
The slope of a line is basically a measure of its steepness.It is basically the difference between y coordinate divided by the difference between x coordinate. We can form an equation with the help of the slope.
Points=(19,-16) and (-7,-15)
Slope=(-15+16)/(-7-19)
=1/-26
=-1/26
Hence the slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Learn more about slope at brainly.com/question/3493733
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First find the length of the hypotenuse using pythagorean theorem
<span>c^2 = 5^2 + 7^2
c^2 = 25 + 49
c^2 = 64
c=8 (take the square root in both sides)
Since sin = opposite/hypotenuse,
sin = 5/8 = 0.625</span>
Answer:
65°
Step-by-step explanation:
JM = JK (all sides of a rhombus are equal)
Angle JKM = 25° (isosceles triangle)
Angle JKL = 50° (consecutive angles of rhombus)
Angle MKL = 25° (angle subtraction)
Angle MLK = 130° (opposite angles of a rhombus)
Angle KLN = 50° (angles on a straight line)
Angle LKN = 40° (angle sum of triangle)
Angle MKN = 65° (angle addition)
Answer:
I believe it is: 6n+8+7y+4m
Step-by-step explanation:
You can't do anything about the numbers with variables afterwards, so you just list those and you just add and subtract the numbers without variables. Since the top and bottom are the same, you just list it once. Sorry, not the best explanation. Please let me know if I am wrong. It's been a while since I had to any type of algebra.