Remember, you take 1/2 of b and square it to get c
c=100
(b/2)^2=c
(b/2)^2=100
sqrt oth sides
b/2=+/-10
times both sides by 2
b=+/-20
it is 20 or -20
answe ris B
yo is right
Answer:
The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344
Step-by-step explanation:
56% of the students are involved in a sport team
56% = 0.56
According to the question, it is stated that 24% of the students at the school that are involved in a sports team also participated in the prom dance.
24% = 0.24
This means that we are going to find 24% of the original 56%, since 24% of them also participated in the prom dance.
The probability that a student who is involved in a sports team also participated in the prom dance = 0.24 * 0.56
The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344
19. -x-2 = 2/3x + 3
5/3 x + 3 = -2
5/3x = -5
x = -3
20. none are correct, you can double check me by plugging in the x and y values in the coordanates into the first problem none of them worked out in the first equasion so no need to test the second
21. -3 is the answer, capable of being done by using desmos
The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 
Therefore, the pool can hold 65.84 ft³ of water
