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Alborosie
3 years ago
15

Find the values of x and y.

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

it is just google it

Step-by-step explanation:

i mean just search it up on google a thing called hamsterx gives you the answere

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HELP PLS IM DUM
Andrews [41]

ur not dum

Answer:

Paul

Step-by-step explanation:

Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.

Computing the return of both

Monica return is  100*3.4%= $3.4 in a year

Paul return is 200*%2.2=  $4.4 in a year.

5 0
2 years ago
You invest $9000 with a 6% interest rate compounded semiannually. After 9 yrs, how much money is in your account?
astraxan [27]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$9000\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\

t=years\to &9
\end{cases}
\\\\\\
A=9000\left(1+\frac{0.06}{2}\right)^{2\cdot 9}
7 0
3 years ago
If you help me i will love you
blagie [28]
You must first normalize this in order to use a Z-score table. To convert what you have into a Z score you must use this formula: (x- mean) /standard deviation. In your case (334-310)/12=2. So now you want the probability that a score is greater than 334, which in turn means you want P(Z>2)=1-P(Z<2)=1-.9772=0.0228=2.28%.
5 0
3 years ago
Is 4 18/12 equal to 5 6/12?
Tom [10]

Answer:

Yes, 4 18/12 is equal to 5 6/12.

Step-by-step explanation:

Given that

4 18/12 = 5 6/12

11/2 = 11/2

Yes both are equal.

7 0
3 years ago
A research company desires to know the mean consumption of meat per week among people over age 40. A sample of 610 people over a
Papessa [141]

Answer: (3.0,\ 3.2)

Step-by-step explanation:

Confidence interval for population mean is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}  (1)

, where \overline{x} = Sample mean

z_{\alpha/2}= Critical z-value

\sigma = Population standard deviation.

n= Sample size.

As per given , we have

n= 610

\sigma=1.1

\overline{x}=3.1

Significance level for 85% confidence : \alpha=1-0.85=0.15

By z-table critical two tailed z-value : z_{\alpha/2}=z_{0.075}=1.44

Put all values in (1) , we get

3.1\pm 1.44\dfrac{1.1}{\sqrt{610}}

3.1\pm 1.44\dfrac{1.1}{24.698}

3.1\pm 0.064

=(3.1-0.064,\ 3.1+0.064)=(3.036,\ 3.164)\approx(3.0,\ 3.2)

Hence, the 85% confidence interval for the mean consumption of meat among people over age 40.  = (3.0,\ 3.2)

5 0
3 years ago
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