What is a difference of squares that has a factor of x+8?

Mathematics

2 answers:

klemol [59]3 years ago

8 0

Answer:

its c

Step-by-step explanation:

did it on edgunity

uysha [10]3 years ago

7 0

Answer:

x^2 - 64

Step-by-step explanation:

A difference of squares is a special product in the form (a^2 - b^2)..their factored form is (a - b)(a + b)..

Thus here a = x and b = 8, thus if x + 8 is a factor, then x - 8 is also a factor..

(x + 8)(x - 8) <-- expand this out using difference of squares rules..

= (x)^2 - (8)^2

= x^2 - 64 <-- answer...

You could also expand that using FOIL (FOIL - first, outer, inner, last)..

(x + 8)(x - 8)

= (x)(x) + (x)(-8) + (8)(x) + (8)(-8)

= x^2 - 8x + 8x - 64 <-- the -8x and 8x cancels out..leaving you with..

= x^2 - 64

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Hope this helps.