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oksian1 [2.3K]
3 years ago
7

What is a difference of squares that has a factor of x+8?

Mathematics
2 answers:
klemol [59]3 years ago
8 0

Answer:

its c

Step-by-step explanation:

did it on edgunity

uysha [10]3 years ago
7 0

Answer:

x^2 - 64

Step-by-step explanation:

A difference of squares is a special product in the form (a^2 - b^2)..their factored form is (a - b)(a + b)..

Thus here a = x and b = 8, thus if x + 8 is a factor, then x - 8 is also a factor..

(x + 8)(x - 8) <-- expand this out using difference of squares rules..

= (x)^2 - (8)^2 

= x^2 - 64 <-- answer...

You could also expand that using FOIL (FOIL - first, outer, inner, last)..

(x + 8)(x - 8) 

= (x)(x) + (x)(-8) + (8)(x) + (8)(-8) 

= x^2 - 8x + 8x - 64 <-- the -8x and 8x cancels out..leaving you with..

= x^2 - 64

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Step-by-step explanation:

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Required

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This question illustrates binomial distribution and will be solved using;

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And will be calculated using:

P(x \ge 3) = P(x = 3) + P(x = 4) + P(x = 5)

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P(x = 4) = ^5C_4 * (0.35)^4 * (1 - 0.35)^{5-4}

P(x = 4) = 5 * (0.35)^4 * (1 - 0.35)^1

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P(x = 4) = 0.0488

P(x = 5) = ^5C_5 * (0.35)^5 * (1 - 0.35)^{5-5}

P(x = 5) = 1 * (0.35)^5 * (1 - 0.35)^0

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P(x \ge 3) = P(x = 3) + P(x = 4) + P(x = 5)

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