Answer:
![a.\hspace{3} \frac{6}{38} = 0.15789474\\\\b.\hspace{3} \frac{45}{55} = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 0.14285714\\\\d.\hspace{3} \frac{35}{28} = 1.25\\\\e.\hspace{3} \frac{1030}{2030} = 0.50738916](https://tex.z-dn.net/?f=a.%5Chspace%7B3%7D%20%5Cfrac%7B6%7D%7B38%7D%20%3D%200.15789474%5C%5C%5C%5Cb.%5Chspace%7B3%7D%20%5Cfrac%7B45%7D%7B55%7D%20%3D%200.81818181%5C%5C%5C%5Cc.%5Chspace%7B3%7D%20%5Cfrac%7B4%7D%7B28%7D%20%3D%200.14285714%5C%5C%5C%5Cd.%5Chspace%7B3%7D%20%5Cfrac%7B35%7D%7B28%7D%20%3D%201.25%5C%5C%5C%5Ce.%5Chspace%7B3%7D%20%5Cfrac%7B1030%7D%7B2030%7D%20%3D%200.50738916)
Step-by-step explanation:
Rational numbers, expressed as decimal numbers, are obtained from the operation of division between the integer of the numerator and the integer of the denominator. Then:
![a.\hspace{3} \frac{6}{38} = 6\div38 = 0.15789474\\\\ b.\hspace{3} \frac{45}{55} = 45\div55 = 0.81818181\\\\c.\hspace{3} \frac{4}{28} = 4\div28 = 0.14285714\\\\ d.\hspace{3} \frac{35}{28} = 35\div28 = 1.25\\\\ e.\hspace{3} \frac{1030}{2030} = 1030\div2030 = 0.50738916](https://tex.z-dn.net/?f=a.%5Chspace%7B3%7D%20%5Cfrac%7B6%7D%7B38%7D%20%3D%206%5Cdiv38%20%3D%200.15789474%5C%5C%5C%5C%20b.%5Chspace%7B3%7D%20%5Cfrac%7B45%7D%7B55%7D%20%3D%2045%5Cdiv55%20%3D%200.81818181%5C%5C%5C%5Cc.%5Chspace%7B3%7D%20%5Cfrac%7B4%7D%7B28%7D%20%3D%204%5Cdiv28%20%3D%200.14285714%5C%5C%5C%5C%20d.%5Chspace%7B3%7D%20%5Cfrac%7B35%7D%7B28%7D%20%3D%2035%5Cdiv28%20%3D%201.25%5C%5C%5C%5C%20e.%5Chspace%7B3%7D%20%5Cfrac%7B1030%7D%7B2030%7D%20%3D%201030%5Cdiv2030%20%3D%200.50738916)
Answer:
what are you talking BOUT?
Step-by-step explanation:
Answer:
25 Or A
Step-by-step explanation:
Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)