By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
<h3>How to solve a system of equations</h3>
In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:
x - y = 5 (1)
x² · y = 5 · x + 6 (2)
By (1):
y = x + 5
By substituting on (2):
x² · (x + 5) = 5 · x + 6
x³ + 5 · x² - 5 · x - 6 = 0
(x + 5.693) · (x - 1.430) · (x + 0.737) = 0
There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737
And the y-values are found by evaluating on (1):
y = x + 5
x₁ ≈ 5.693
y₁ ≈ 10.693
x₂ ≈ 1.430
y₂ ≈ 6.430
x₃ ≈ - 0.737
y₃ ≈ 4.263
By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.
To learn more on nonlinear equations: brainly.com/question/20242917
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This is what I found in a calculator
Answer:
A= 1/2(2x)(x+7)
Step-by-step explanation:
Step-by-step explanation:
In my picture I made 6 slices, with one slice twice as large as the others.
Pretend that we cut the sausage slice in half. Then there would be 7 slices total.
We want to find P(Not Sausage).
Well since we sliced the big slice in two, we have 7 slices total. There are 5 slices without sausage.
The probability of getting a slice without sausage would then be 5/7.
Answer: The required probability is 0.414.
Step-by-step explanation:
Since we have given that
Probability of taxis in a certain city by Blue Cab P(B)= 15%
Probability of taxis by Green Cab P(G) = 85%
Let A be the event that eyewitness said that vehicle was blue.
P(A|B)=0.80
P(A|G)=0.80
P(A'|B)=0.20=P(A'|G)
Using the "Bayes theorem":
Probability that the taxi at fault was blue is given by
Hence, the required probability is 0.414.
