A simple diagram will show you the intersection of altitudes is in the 2nd quadrant. It must have x-coordinate -2, as the altitude to the "base" y=10 must be the vertical line through (-2, 4).
The appropriate choice is ...
... C: (-2, 12)
Answer:
p²q³ + pq and pq(pq² + 1)
Step-by-step explanation:
Given
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Required
Collect like terms
We start by rewriting the expression
3p²q² - 3p²q³ +4p²q³ -3p²q² + pq
Collect like terms
3p²q² -3p²q² - 3p²q³ +4p²q³ + pq
Group like terms
(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq
Perform arithmetic operations on like terms
(0) - (-p²q³) + pq
- (-p²q³) + pq
Open bracket
p²q³ + pq
The answer can be further simplified
Factorize p²q³ + pq
pq(pq² + 1)
Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)
The domain is all ur x values...the range is all ur y (or f(x) values
so ur domain is : { -6,-1,0,3}....1st answer choice
The intersection of 2 lines is a point so A. Because that’s where the lines meet then if they keep going they shouldn’t touch again.
