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3 years ago

7. If a school has 70 computers in the ratio of 3 desktops for every 4 laptops, how many

Mathematics

1 answer:

stealth61 [152]3 years ago

6 0

Step-by-step explanation:

As ratio of desktops to laptops=3:4

Take no. of desktops= 3x

Take no. of Laptops=4x

Total no. of desktops+ Total no. of laptops = Total no. of computers

3x+4x=70

7x=70

x=10

Hence, the total no, of desktops= 3x

Hence, Total no. of desktops= 3×10

=30 desktops

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allsm [11]

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2 years ago

The sum of 5 consecutive integers is 120 what is the third number

Juliette [100K]

5 consecutive numbers that add up to 120 are:
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Hope it helps :)

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2 years ago

If 2^n + 1 is an odd prime for some integer n, prove that n is a power of 2. (H

vovikov84 [41]

Step-by-step explanation:

We will prove by contradiction. Assume that $2^n + 1$ is an odd prime but n is not a power of 2. Then, there exists an odd prime number p such that $p\mid n$ . Then, for some integer $k\geq 1$ ,

$n=p\times k.$

Therefore

$2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p.$

Here we will use the formula for the sum of odd powers, which states that, for $a,b\in \mathbb{R}$ and an odd positive number $n$ ,

$a^n+b^n=(a+b)(a^{n-1}-a^{n-2}b+a^{n-3}b^2-...+b^{n-1})$

Applying this formula in 1) we obtain that

$2^n + 1=2^{p\times k} + 1=(2^{k})^p + 1^p=(2^k+1)(2^{k(p-1)}-2^{k(p-2)}+...-2^{k}+1)$ .

Then, as $2^k+1>1$ we have that $2^n+1$ is not a prime number, which is a contradiction.

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2 years ago

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iragen [17]

Answer:

Yes your right

Step-by-step explanation:

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2 years ago

Translate the sentence into an algebraic equation. Use x for the variable.

DENIUS [597]

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I think this would work, if I understood what you were saying correctly.

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3 years ago