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zlopas [31]
3 years ago
6

Read each problem and decide what operation you

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Answer:

b = 3.5 cm

Step-by-step explanation:

Given that,

The area of a rectangle, A = 14. sq cm

The length of one side, l = 4 cm

We need to find the length of another side. The formula for the area of a rectangle is given by :

A = lb

So,

14=4b\\\\b=\dfrac{14}{4}\\\\b=3.5\ cm

So, the length of the other side is equal to 3.5 cm.

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What is the area of the obtuse triangle below?
kolezko [41]

Answer:

198

Step-by-step explanation:

just multiply 22 by 8

8 0
3 years ago
which expression correctly shows the commutative proberty? a)8+14+22+9=(8+14)+(22+9). b)8+14+22+9=8+(14+22)+9. c)8+14+22+9=53. d
Lerok [7]
D has the commutative property because it just flip flopped the numbers.
5 0
3 years ago
Field book of an land is given in the figure. It is divided into 4 plots . Plot I is a right triangle , plot II is an equilatera
Kazeer [188]

Answer:

Total area = 237.09 cm²

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)

From the figure attached,

Area of the right triangle I = \frac{1}{2}(\text{Base})\times (\text{Height})

Area of ΔADC = \frac{1}{2}(\text{CD})(\text{AD})

                        = \frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})

                        = \frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)

                        = \frac{1}{2}(\sqrt{169-144})(12)

                        = \frac{1}{2}(5)(12)

                        = 30 cm²

Area of equilateral triangle II = \frac{\sqrt{3} }{4}(\text{Side})^2

Area of equilateral triangle II = \frac{\sqrt{3}}{4}(13)^2

                                                = \frac{(1.73)(169)}{4}

                                                = 73.0925

                                                ≈ 73.09 cm²

Area of rectangle III = Length × width

                                 = CF × CD

                                 = 7 × 5

                                 = 35 cm²

Area of trapezium EFGH = \frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})

Since, GH = GJ + JK + KH

17 = \sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}

12 = \sqrt{81-x^2}+\sqrt{225-x^2}

144 = (81 - x²) + (225 - x²) + 2\sqrt{(81-x^2)(225-x^2)}

144 - 306 = -2x² + 2\sqrt{(81-x^2)(225-x^2)}

-81 = -x² + \sqrt{(81-x^2)(225-x^2)}

(x² - 81)² = (81 - x²)(225 - x²)

x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴

144x² - 11664 = 0

x² = 81

x = 9 cm

Now area of plot IV = \frac{1}{2}(5+17)(9)

                                = 99 cm²

Total Area of the land = 30 + 73.09 + 35 + 99

                                    = 237.09 cm²

7 0
3 years ago
PLZ HELP 50 POINTS AND BRAINLIEST PLZZZ HELP TIMED!!!
k0ka [10]

Answer:

i think its C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help ASAP. Thanks so much
seropon [69]

Answer:

its A

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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