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4 years ago

What is 12 5//25 as a mixed number in simplest form

Mathematics

2 answers:

algol134 years ago

4 0

12 5/25 is already a mixed number, so all you need to do is simplify.

12 5/25 simplified is 12 1/5.

Ugo [173]4 years ago

3 0

12 5/25 = 12 1/5. Hope it helps you!

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How do you Graph y-3=1/3(x+1)

jekas [21]

Answer:

You can find the point of intersection of the line with the y-axis and the the point of intersection of the line with the x-axis. See the graph attached.

Step-by-step explanation:

Find the intersection with the y-axis. Substitute $x=0$ into the equation and solve for y:

$y-3=\frac{1}{3}(x+1)\\\\y-3=\frac{1}{3}(0+1)\\\\y-3=\frac{1}{3}(1)\\y=\frac{1}{3}+3\\\\y=\frac{10}{3}$

$y$ ≈3.33

Find the intersection with the x-axis. Substitute $y=0$ into the equation and solve for x:

$y-3=\frac{1}{3}(x+1)$

$0-3=\frac{1}{3}(x+1)\\(-3)(3)=x+1\\-9-1=x\\x=-10$

Now, you know that the line passes through the point (0,3.33) and (-10,0). Now you can graph the function. (Observe the graph attached)

6 0

4 years ago

Which mixed number is greater 5 7/24 or 5 5/16

Sauron [17]

5 5/16 is greater.
You can find that out by dividing 5/16 and 7/24
So that gives .31 and .29
Thus, 5 5/16 are greater

3 0

3 years ago

Read 2 more answers

Consider the set whose elements are the graphs having vertex set {1, 2, 3, 4}, and consider the relation on that set, where two

Damm [24]

Answer:

Step-by-step explanation:

Let S be the set of all graphs having vertex set \{1,2,3,4\}. The relation \rho is defined over S such that

the graphs G and H are equivalent provided that they have same number of edges. Then, the number of equivalence classes depends on how many edges can be there in the vertex set \{1,2,3,4\} .

The number of edges is 0 forms a disconnected graph which makes an equivalent class.

The graphs of 1 edge makes an equivalent class.

The graphs of 2 edges makes an equivalent class.

The graphs of 3 edges makes an equivalent class.

The graphs of 4 edges makes an equivalent class.

The graphs of 5 edges makes an equivalent class.

In similar way, the only graph of 6 edges is complete graph which forms another equivalent class.

Hence,the total number of equivalent classes is 7.

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3 years ago

The volume of a cone is 1/3 that of a cylinder when the radius and height are the same (v= 1/3(pi)(r)^2(h). What is the volume o

Ira Lisetskai [31]

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Surface Areas and Volumes.

Since, Volume of cone = 1/3 π r^2 h,

here, r = 10 Inches and h= 12 inches, also π =3.14

so, VOC = 1/3 π (10)^2 × (20)

VOC = 1/3(3.14)(100)(20)= 2093.33 inch^3

=> so the volume of the cone is 2093.33 cubic inches.

5 0

3 years ago

Which term describes the set of all possible output values for a function?

dexar [7]

The set of all output values for a function is called the range.

3 0

3 years ago

Read 2 more answers