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wariber [46]
4 years ago
9

Solve for : -21 = 0.07:

Mathematics
1 answer:
Natasha2012 [34]4 years ago
5 0

Answer:

-300

Step-by-step explanation:

-21 = 7x/100

-21=7x/2^2*5^2

x=-300

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The perimeter of a quadrant of a circle is 71.4cm. Find its area ​
Karolina [17]

Answer:

circle: 6490.9 cm², quadrant: 1622.7 cm²

Step-by-step explanation:

The circumference of the entire circle is known as 2πr and it is 4 times the given value, since a circle has 4 quadrants:

2πr = 4·71.4 = 285.6, so r = 285.6 / 2π ≈ 45.45

The area of a circle is πr², filling in the value for r we just found:

πr² = π 45.45² ≈ 6490.9 cm²

So the area of a quadrant is one fourth of that:

6490.9/4 = 1622.7 cm²

The question about "its area" can denote the entire circle, or just the quadrant, so two answers are provided.

8 0
2 years ago
Read 2 more answers
Chord JK intersects chord ST at point L. Find the length of St. If necessary, round to the tenths place.
raketka [301]

Answer:

(C)19

Step-by-step explanation:

The diagram is drawn and attached.

Using the intersecting chord theorem

SL X LT = JL X LK

x X 12 = 14(x-1)

12x=14x-14

12x-14x=-14

-2x=-14

x=7

Therefore:

ST= SL + LT

=x+12

=7+12

ST=19

The correct option is C

5 0
3 years ago
Work out the sum of 8.2 and 949.65.
olga2289 [7]

Answer:

957.85

Step-by-step explanation:

  949.65

+     8.2

_________

   957.85

7 0
3 years ago
Read 2 more answers
Which pilgrim dresses in red and blue?
olya-2409 [2.1K]
Please answer. Quickly.
8 0
3 years ago
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How to do question 1?Had no idea how to do both parts
givi [52]
y=\dfrac{\ln x}{3x-6}

Differentiate both sides with respect to x:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}

When x=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13

For part (b), we now assume that x and y are functions of an independent variable, which we'll call t (for time). Now differentiating both sides with respect to t, we have

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}

where the chain rule is used on the right side. We're told that y is decreasing at a constant rate of 0.1 units/second, which translates to \dfrac{\mathrm dy}{\mathrm dt}=-0.1. So when x=1, you have

-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}
-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}
\dfrac{\mathrm dx}{\mathrm dt}=0.3

where the unit is again units/second.
6 0
3 years ago
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