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wariber [46]
3 years ago
9

Solve for : -21 = 0.07:

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

-300

Step-by-step explanation:

-21 = 7x/100

-21=7x/2^2*5^2

x=-300

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Help pls I really need it
Talja [164]

Answer:

Infinite number of solutions

Step-by-step explanation:

when you solve for V, you notice that the term in "v" goes away, and you end up with a true statement:

2 = 2

This is a true statement no matter what values the variable V has, so it is true for all possible (infinite) values of "v".

8 0
3 years ago
Will I ever get an answer?
JulsSmile [24]
(5/8) / (3/8) =
5/8 * 8/3 =
5/3 =
1 2/3....a = 1, b = 2, c = 3
5 0
3 years ago
The weight of strawberries follows a normal distribution with a mean weight of 12 grams and a standard deviation of 2.5 grams. I
Viefleur [7K]
This is a problem of Standard Normal distribution.

We have mean= 12 grams
Standard Deviation = 2.5 grams

First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:

z= \frac{8.5-12}{2.5} =-1.4

So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808

Thus, the <span>probability that the strawberry weighs less than 8.5 grams is 0.0808</span>
6 0
3 years ago
Does the table represent a function? Why or why not?
Vinvika [58]

Answer:

Let's put the chart into ordered pairs:

(x, y)

(2,1)

(3,4)

(3,3)

(4,2)

(5,5)

In bold, we see that there are two y-values at x=3. This means that this relation fails the vertical line test (two points on the same verticle line). This is not a function. 

The answer options may be mis-written. 

The answer is no, because one x value corresponds to more than one y-value. 

6 0
3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
4 years ago
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