3 years ago

Select expressions that are equivalent to 5x - 15 - 20x + 10

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

Answer:

-15x - 5

Step-by-step explanation:

5x - 15 - 20x + 10

5x - 20x - 15 + 10

-15x - 5

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Match each statement using only the information shown in the pairs of congruent triangles.

pogonyaev

Answer in the link above

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3 years ago

Which expression shows the result of simplifying 1/5x+4−2/5x−2by combining like terms? a 2+3/5x B 2−1/5x C 6−1/5x D 6+3/5x

natka813 [3]

<span>1/5x+4−2/5x−2
</span>= -1/5x + 2
= 2 - 1/5x

answer
B. 2−1/5x

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3 years ago

The owner of a local farm sells baskets of fresh tomatoes in the summer time. Each basket is priced according to its mass rounde

elixir [45]

Answer:

4 1/10 kg

Step-by-step explanation:

To find the total mass, we add the mass of the three baskets

1 1/10 + 1 3/10 + 1 7/10

Since they have the same denominator

1 1/10

1 3/10

1 7/10

-------------

3 11/10

Change the improper fraction to a mixed number

11/10 = 1 1/10

3 + 1 1/10

4 1/10

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3 years ago

Which function is the inverse of g(x)=2*∛(x−3)+4

Rama09 [41]

Answer:

(((x-4)/2)^3)+3=y

Step-by-step explanation:

You just have to switch the y and the x and then isolate the y

6 0

2 years ago

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

7 0

3 years ago