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Alexxandr [17]
3 years ago
13

The coach of a softball team is holding tryouts and can take only 2 more players for the team. there are players 8 trying out. h

ow many different groups of 2 players could possibly be chosen?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0
The order in which the two players will be selected from the 8 trying players is not important. The most important thing is to have the two players.
Therefore, this is a question of combination.

The number of groups = 8C2 = 8!/[2!*(8-2)!] = (8*7*6*5*4*3*2*1)/[(2*1)*(6*5*4*3*2*1)] = 28 groups
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<h2>Hello!</h2>

The answer is $101688

<h2>Why?</h2>

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<h2>Calculations</h2>

Let's say:

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