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jasenka [17]
3 years ago
10

Write an expression for the calculation the sum of the product of 4 and 3 and 1 and 1

Mathematics
1 answer:
inysia [295]3 years ago
6 0

The expression would be: 4*3+1+1


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475 in scientific notation
Mashutka [201]

Answer:

Step-by-step explanation:

4.75 x 10^{2}

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3 years ago
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Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
3 years ago
There are 30 seventh grade students in the cafeteria. In a representative sample of 25 students, there are 14 girls. Estimate th
Basile [38]

Answer:

17 i think

Step-by-step explanation:

7 0
3 years ago
If any one answer this question i will give them brainliest
frozen [14]

Answer:

x =9

Step-by-step explanation:

-5x = -45

Divide both sides by -5:

x = 9

5 0
3 years ago
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Which expression shows the distance on the number line between −12 and −1 ?
Naddik [55]

Answer: A or D i think sorry if wrong but a i think

Step-by-step explanation:

but The distance between A and B = |B - A|

We have -12 and -1.

Substitute:

|-1 - (-12)| = |-1 + 12| = |11| = 11

Answer: 11 units

6 0
3 years ago
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