Answer:
The probability of missing the first metal-carrying person is P(x≤50)=0.395
Step-by-step explanation:
We define as success to: missing metal carrying detection.
p=0.01
P(x)=
We look for the probability when all metal carring people is detected so x=0
P(x≤50)=1-P(x=0)=
=0.395
Answer:
D m = 
Step-by-step explanation:
factor the expressions in the denominator and the numerator to simplify the expression:
=> 
=> 
to make a fraction undefined, the numerator should be 0, thus, we substitute the values of m from the options into the denominator to make the denominator equals to 0:
=>
=
= 
in this case, the values of m from option D make the denominator of the fraction equals 0.
Let X= the number of tickets sold at $35 each
Let 350 -X = the number of tickets sold at $25 each
The number of tickets sold for each type will be computed as follows:
X(35)+(350-X)25=10250
35X+8750-25X=10250
10X=10250-8750
X=1500/10
X=150 the number of tickets sold at $35 each
350-150 the number of tickets sold at $25 each
To recheck:
150(35)+200(25)
5250+5000
10250
The answer is
B. A dot plot is shown with the title Match Scores. There are 2 dots over score 1, 3 dots over score 2, 2 dots over score 3, 1 dot over score 4, and 2 dots over score 5.
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