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lutik1710 [3]
3 years ago
7

Please help me fast! I will give brainliest, if you show your work, and it is the right answer. Four lines are drawn on a coordi

nate plane to form trapezoid WXYZ. Which statements are true about the lines? SELECT ALL THAT APPLY. Line WZ has the same slope as line XY. Line YX has a greater slope than line ZY. Line XW has a lesser slope than line YZ. Line ZW has the same y-intercept as line WZ. Line XY has a greater y-intercept than line XW.
Mathematics
1 answer:
mars1129 [50]3 years ago
6 0
B,C,E is the correct answer
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Help me I need at least a B in 7th grade math
Leya [2.2K]

For part a, yes because each student is paying the same amount

For part c, each student is paying $15 to go

For part d, it's $1800

For part e, it would be 95 students

8 0
3 years ago
Gas is being pumped into a tank the total amount of gas G after amount of time T is given by the equation G= 50+20t if the total
luda_lava [24]

Answer:

T = 40 (minutes?)

Step-by-step explanation:

Given the equation G = 50 + 20T, where G = the total amount of gas and T = the amount of Time, we know that there is already 50 gallons of gas in the tank and that the rate at which it is pumped is 20 gallons per minute (I am assuming, though it is not stated in the problem).  Given that the tank holds 850 gallons, we can plug in the values into the equation and solve for the missing variable, T:

850 = 50 + 2T

Subtract 50 from both sides:  850 - 50 = 50 + 2T - 50 or 800 = 2T

Divide 2 from both sides: 800/2 = 2T/2

Solve for T:  40 = T

3 0
3 years ago
For each set of three measures determine if they can be angle measures of a triangle
Orlov [11]

Only the second set of measures qualifies as angle measures of a triangle. Angles 25°, 130°, 25°

Step-by-step explanation:

  • Step 1: To find whether angles qualify as angle measures of a triangles, calculate their total sum and verify whether they add up to 180°

Set 1 - 41° + 112° + 52° = 205°

Set 2 - 25° + 130° + 25° = 180°

Set 3 - 30° + 40° + 90° = 160°

Set 4 - 132° + 141° + 31° = 304°

Therefore, only set 2 qualifies.

8 0
3 years ago
Solve x and y please need it for tomorrow
Evgen [1.6K]
Solve for x by cross multiplying then isolating the variable:
\frac{9}{15}= \frac{x}{10}                     cross multiply
15x=90                     Isolate the variable
x=6
Solve for y by cross multiplying then isolating the variable:
\frac{9}{15} = \frac{6}{y}          cross multiply
9y=90               Isolate the variable
y=10
4 0
3 years ago
Read 2 more answers
The probability of flu symptoms for a person not receiving any treatment is 0.038. In a clinical trial of a common drug used to
alexgriva [62]

Answer:

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1164, p = 0.038

So

\mu = E(X) = np = 1164*0.038 = 44.232

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = 6.5231

Estimate the probability that at least 47 people experience flu symptoms.

Using continuity correction, this is P(X \geq 47 - 0.5) = P(X \geq 46.5), which is 1 subtracted by the pvalue of Z when X = 46.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.5 - 44.232}{6.5231}

Z = 0.35

Z = 0.35 has a 0.6368

1 - 0.6368 = 0.3632

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

6 0
2 years ago
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