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vodka [1.7K]
3 years ago
8

Colleen rode her bicycle 9.5 miles in 0.8 hour. What was her average speed in miles per hour? a 11.875 miles per hour b 10.3 mil

es per hour c 8.7 miles per hour d 7.6 miles per hour
Mathematics
2 answers:
slava [35]3 years ago
3 0

Answer:

Collen's average speed was 11.875 miles/h

Step-by-step explanation:

The average speed is given by the total distance travelled divided by the time at which the route was completed. So in this case the total distance is 9.5 miles and the time to complete it was 0.8 hour. We then have:

average speed = total distance/ time

average speed = 9.5/0.8 = 11.875 miles/h

Collen's average speed was 11.875 miles/h

zhenek [66]3 years ago
3 0

Answer:

Option a: 11.875 miles per hour

Step-by-step explanation:

We can calculate Colleen's average speed using a rule of three:

She rode a total of 9.5 miles in 0.8 hours, so how much she would rode in 1 hour (this way we can calculate her speed in miles per hour)

9.5 miles -> 0.8 hours

X miles -> 1 hour

9.5/X = 0.8

X = 9.5 / 0.8 = 11.875 miles per hour

The correct option is option "a".

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If x varies directly with y and x = 2.5 when y = 10, funny x when y = 16.
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Answer:

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Step-by-step explanation:

If y=10 and x =2.5, if y were to = 20, then x would equal 5. so you take that ratio, and say 6 is 3/5's the way to 10, so you also divide 2.5 by 3/5

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3 years ago
The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with
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Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

\frac{7}{8} = 0.875

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

= \frac{7}{8 - 7}

= 7

(c) Average time in minutes before service

= λ/[μ(μ - λ)]

= \frac{7}{8(8 - 7)}

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

= \frac{1}{(8 - 7)}

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

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{7}{8}

= 0.875

5 0
3 years ago
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