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expeople1 [14]
3 years ago
10

A grid shows the positions of a subway stop and your house. The subway stop is located at (7,-4) and your house is located at (-

3,6). What is the distance, to the nearest unit, between your house and the subway stop.

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0
Image a right triangle with two points at these two locations and the hypothenuse as the distance between them.
Find the length straight down from the first point to the second: 10 units
Find the length to the right from the first point to the second: 10 units
Use the Pythagorean theorem: a^2 + b^2 = c^2
10^2 + 10^2 = 200
√200 = 10√2 = 14.14 units
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What is the sum of 2/11’ 2/7’ and 1/11’?
pav-90 [236]
Solution

To solve this addition of fractions we are gonna apply the fraction rule which is;

a/c + b/c = (a + b)/c

2/11 + 1/11 = (2 + 1)/11


= (2 + 1)/11 + 2/7

Now add the numerators 2 + 1

= (2 + 1)/11 + 2/7

= 3/11 + 2/7

Now we find the least common multiple

The least common multiple of 11 and 7 is 77.

But before that we cross multiply the numerators.

3 * 7 = 21
2 * 11 = 22

Now the ajustes fraction is;

21/77 + 22/77


Apply the fraction rule which is;

a/c + b/c = (a + b)/c

= (21 + 22)/77

Now we add the numerators.

43/77

Therefore the answer in fraction is 43/77 and in decimal form it is 0.55841
6 0
3 years ago
How do I do this plz help me out
Nataliya [291]
It's saying that B is equal to 1, and c is equal to 4. So your gonna square B (multiply it by itself) and add c. Make sense?
6 0
4 years ago
A quantity with an initial value of 600 decays exponentially at a rate of
Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

Q(t) = 600(1 - 0.0005)^{t}

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

Q(t) = 600(1 - 0.0005)^{t}

Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64

The value of the quantity after 87 months will be of 599.64.

8 0
3 years ago
(5x-2)^2 help asap pleaseee
omeli [17]

Answer:

25x² − 20x + 4

Explanation:

(5x − 2)²

= (5x + −2)(5x + −2)

= (5x)(5x) + (5x)(−2) + (−2)(5x) + (−2)(−2)

= 25x² − 10x − 10x + 4

= 25x² − 20x + 4

5 0
3 years ago
Can someone double check me???
kvv77 [185]
You’re correct I think
8 0
3 years ago
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