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expeople1 [14]
3 years ago
10

A grid shows the positions of a subway stop and your house. The subway stop is located at (7,-4) and your house is located at (-

3,6). What is the distance, to the nearest unit, between your house and the subway stop.

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0
Image a right triangle with two points at these two locations and the hypothenuse as the distance between them.
Find the length straight down from the first point to the second: 10 units
Find the length to the right from the first point to the second: 10 units
Use the Pythagorean theorem: a^2 + b^2 = c^2
10^2 + 10^2 = 200
√200 = 10√2 = 14.14 units
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X to the power of 3 - 7x + 6 factorise please whole step by step​
Over [174]

Answer:

(x     +  3)(x   -  2)(x - 1)

Step-by-step explanation:

{x}^{3}  - 7x + 6

Factor using Rational Root Theorem.

This means our possible roots are

positve or negative (1,2,3,6). If we try positve 1, it is indeed a root.

This means that

(x - 1)

is a root.

We can divide the top equation by the root (x-1). Our new equation is

( {x}^{2}   +  x - 6)

Now we can factor this completely

(x + 3)(x - 2)

So this equation in factored form is

(x  + 3)(x - 2)(x - 1)

8 0
3 years ago
Which is the domain of the function f(x) = -5/6(3/5)x ?
Ghella [55]

The domain would be (negaive infinity, positive infinity)

8 0
3 years ago
Find the ratio y:x, if 3x=11y,
Aleks [24]

Answer:

3:11

Step-by-step explanation:

3x=11y

<u>Rearrange to the format of the ratio.</u>

11y = 3x

<u>Let's find </u><u>y/x</u><u>. </u><u>y/x</u><u> is </u><u>y:x.</u>

11y = 3x

<u>Divide both sides by </u><u>11</u><u>.</u>

11y/11 = 3x/11

y = 3x/11

<u>NOW LET'S DIVIDE BOTH SIDES BY </u><u>x</u><u> TO GET </u><u>x</u><u> AS THE DENOMINATOR OF </u><u>y</u><u>.</u>

y = 3x/11

y/x = (3x/11)/x

y/x = (3x/11) * 1/x

y/x = 3/11

Therefore, y:x = 3:11

Please thank, rate 5 stars, and give brainliest. Thank you.

7 0
3 years ago
Calculus 3 chapter 16​
o-na [289]

Evaluate \vec F at \vec r :

\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k

Compute the line element d\vec r :

d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt

Simplifying the integrand, we have

\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt

Then the line integral evaluates to

\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}

3 0
1 year ago
There are approximately 39.97 inches in 1 meter. How many meters are there in 240 inches
sladkih [1.3K]
1/39.97=x/240
x= 6

about 6 meters
8 0
3 years ago
Read 2 more answers
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