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uranmaximum [27]

3 years ago

12

ANSWER PLEASE QUICK!! I AM ON A TIMERRR

1 answer:

Fynjy0 [20]3 years ago

5 0

Answer:

smaller x is to the power of 2 3x is the larger.

Step-by-step explanation:

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Solve image below:

ludmilkaskok [199]

Answer: $x=\frac{6}{-3y+8}$

Step-by-Step Explanation:

Let's solve for $x$ .

$\frac{x-2}{3y-5} =\frac{x}{3}$

Step 1: Multiply both sides by $3y-5$ .

$x-2=\frac{3xy-5x}{3}$

Step 2: Multiply both sides by $3$ .

$3x-6=3xy-5x$

Step 3: Add $-3xy$ to both sides.

$3x-6+-3xy=3xy-5x+-3xy$

$-3xy+3x-6=-5x$

Step 4: Add $5x$ to both sides.

$-3xy+3x-6+5x=-5x+5x$

$-3xy+8x-6=0$

Step 5: Add $6$ to both sides.

$-3xy+8x-6+6=0+6$

$-3xy+8x=6$

Step 6: Factor out variable $x$ .

$x(-3y+8)=6$

Step 7: Divide both sides by $-3y+8$ .

$\frac{x(-3y+8)}{-3y+8}=\frac{6}{y-3y+8}$

$x=\frac{6}{-3y+8}$

Answer:

$x=\frac{6}{-3y+8}$

4 0

2 years ago

Which system of the equation is represents by the graph?<br><br><br>

pashok25 [27]

Sorry just needed points to use this app

3 0

2 years ago

What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3?

Marrrta [24]

C

the sum to infinity of a geometric series = $\frac{a}{1-r}$

where a is the first term and r the common ratio

= $\frac{81}{\frac{1}{3} }$ = 81 × 3 = 243

4 0

3 years ago

A cell phone company $500 for a new phone and $60 for a monthly plan. If C(t) is a rational function that represents the average

lisov135 [29]

The range of a function is the set of possible values that can be obtained from the dependent variable. The range of the function is: $R: (500, \infty)$

Given that:

$Phone = \$500$

$Monthly\ Plan = \$60$

Let the number of months be t. So, the function C(t) is calculated as follows:

$C(t) = Phone + Monthly\ Plan \times t$

$C(t) = 500 + 60 \times t$

$C(t) = 500 + 60t$

The range is calculated as follows:

The smallest possible value of t is 0 i.e. when no monthly subscription is done.

So, we have:

$C(0) = 500 + 60\times 0= 500 + 0 = 500$

And the highest is $\infty$ i.e. for a large value of t

So, we have:

$C(\infty) = 500 + 60\times \infty= 500 + \infty = \infty$

Hence, the range of the function is:

$R: (500, \infty)$

Read more about range of functions at:

brainly.com/question/13824428

5 0

3 years ago

Which expressions is equivalent ?

agasfer [191]

<h3>3 Answers: Choice C, Choice D, Choice F</h3>

What these expressions have in common is that their exponents multiply to 16

(-4)*(-4) = 16 for choice C
(-2)*(-8) = 16 for choice D
8*2 = 16 for choice F

The rule used here is (a^b)^c = a^(b*c). We multiply the exponents and keep the base the same.

7 0

3 years ago