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Lostsunrise [7]
3 years ago
12

I need help with part a and b, please help

Mathematics
1 answer:
yarga [219]3 years ago
3 0
A. so the entire length of the to would be 25. You know 9 of those feet are not rope so you would subtract that from 25
25-9=16
16 would be the all the rope on top and you only want one side, so you would divide it by 2. The top right piece of rope would be 8ft long
Part b is the picture

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Point A is at (-1, -9) and point M is at (0.5, -2.5).
vladimir2022 [97]

Answer:

Point B is located at point (2, 4)

Step-by-step explanation:

Since point M is at the center, you find the distance from point A and add that to the other side.

| -1 - 0.5 | = | -1.5 | = 1.5

| -9 - -2.5 | = | -6.5 | = 6.5

Now we can add that to point M to find point B

0.5 + 1.5 = 2

-2.5 + 6.5 = 4

Point B should be at (2, 4)

4 0
3 years ago
Which of the following represents the difference between the central angles of the above regular polygons? Round to the nearest
solong [7]

Answer:

its 15.43

Step-by-step explanation:

you didnt put a picture for the polygons but im pretty sure this is from math nation.

6 0
3 years ago
I will mark you brainliest if you help me im not lying
aksik [14]

Answer:

60 miles

I hope this helps.

5 0
3 years ago
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You work for a horse farrier. You take a random sample of 75 Quarter Horses and determine that their mean height is 15.2 hands.
Evgesh-ka [11]

Answer:

B) You conclude that the mean height of all Quarter Horses is close to 15.2 hands

Step-by-step explanation:

5 0
3 years ago
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A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular custome
Ludmilka [50]

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), <em>p</em> = 0.52

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 5 and <em>p</em> = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\\\\={5\choose 4}(0.52)^{4}(1-0.52)^{5-4}+{5\choose 5}(0.52)^{5}(1-0.52)^{5-5}\\\\=0.175478784+0.0380204032\\\\=0.2134991872\\\\\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X

Thus, the probability that the flight has empty seats is 0.4625.

4 0
3 years ago
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