Measure the volume by counting the cubic units.

What is the area of triangle pqr on the grid? a triangle pqr is shown on a grid. the vertex p is on ordered pair 7 and 6, vertex

horsena [70]

P(7,6), Q(1,6), R(4,2)

We have PQ parallel to the x axis. We'll call that the base,

b = 7 - 1 = 6

The altitude is then the y difference h = 6 - 2 = 4

The area is $\frac 1 2 bh = \frac 1 2 (6)(4) = 12$

Answer: 12 square units

In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:

(7,6), (1,6), (4,2)

(1,6), (4,2), (7,6)

The area is then half the absolute value of the sum of the cross products:

$A = \frac 1 2 | 7(6)-6(1) + 1(2)-6(4) + 4(6)-2(7) | = \frac 1 2 |24| = 12$

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP ITS GEOMETRY

Gwar [14]

The missing options that makes up the distance formula between two coordinates are; (x₂ - x₁)² and d²

How to find the distance between two coordinates?

The formula for distance between two coordinates is;

d = √[(y₂ - y₁)² + (x₂ - x₁)²]

where;

(x₁, y₁) is the coordinate of the first point

(x₂, y₂) is the coordinate of the second point

Now, this distance formula can also be rewritten when we square both sides to get;

(y₂ - y₁)² + (x₂ - x₁)² = d²

Thus, the missing options that makes up the distance formula between two coordinates are; (x₂ - x₁)² and d²

Read more about distance between two coordinates at; brainly.com/question/7243416

#SPJ1

4 0

2 years ago

Two angles form a linear pair. One angle measures (10x - 63). The other angle measures (8x)". What is the value of the larger

EleoNora [17]

Answer:

108 degrees

Step-by-step explanation:

Given

Let the angles be A and B

$A = 10x - 63$

$B = 8x$

Required

Find the larger angle

If both angles form linear pair, then the following relationship exist:

$A + B = 180$

Substitute values for A and B

$10x - 63 + 8x = 180$

Collect Like Terms

$10x + 8x = 180 + 63$

$18x = 243$

Solve for x

$x = \frac{243}{18}$

$x = 13.5$

Substitute 13.5 for x in

$A = 10x - 63$

$B = 8x$

$A= 10 * 13.5 - 63$

$A= 135 - 63$

$A= 72$

$B = 8 * 13.5$

$B = 108$

Hence, the larger angle measures 108

4 0

3 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago

Need help on precalcues

Vinvika [58]

5 ≥ 2, so the second rule of C(x) applies :

C (5) = 25 + 3•(5 - 2) = 25 + 3•3 = 25 + 9 = 34

7 0

3 years ago