The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer:


Step-by-step explanation:
Connecting points O and E and points O and J, we get triangle EOJ. This triangle is equilateral triangle, because OJ=OE=JE=r=10 cm.
Since EP⊥IJ, then segment JP is the height of the triangle EOJ.
The height of the equilateral triangle can be found using formula

where a is the side length.
So,

Therefore JP is 5√3 cm
Answer: theres a answer key in the last slide & its 15 somehow...
440...marked down by 30% means u pay 70%
70% of 440 = 0.70(440) = 308
308 ..marked down by 10% means u pay 90%
90% of 308 = 0.90(308) = 277.20 <== price after markdowns
Answer:
I really don't know but this is a bad guess 11 inches but don't hold me accountable