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Novay_Z [31]
3 years ago
12

You deposit $6,800 in a money-market account that pays an annual interest rate of 5.7%. The interest is compounded quarterly. Ho

w much money will you have after 3 years?
Mathematics
1 answer:
OleMash [197]3 years ago
5 0
<span>If you deposit(P) $6,800 in a money-market account that pays an annual interest rate(r) of 5.7%. The interest is compounded quarterly(4). [ The money you have after 3 years(t) is: Using the compound interest formula A=P(1+r/n)^nt, where P=$6800, r=57%=.057,t=+3, n=4. A=$6,800(1+(0.057/4))^(3x4) =$6,800(1+0.01425)^12 =$6,800(1.01425)^12 =$6,800(1.18505961016) =$8,058.41. ]</span>
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F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
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Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

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