The "sample" with "mean absolute deviation" indicate about a sample mean absolute deviation is being used as an estimator of the mean absolute deviation of a population
- Mean of the sample MAD=3.3
- Population MAD =6.4
<h3>What does this indicate about a sample mean absolute deviation used as an estimator of the mean absolute deviation of a population?</h3>
Generally, The MAD measures the average dispersion around the mean of a given data collection.
In conclusion, for the corresponding same to mean
the sample mean absolute deviation
7,7 ↔ 0
7,21 ↔ 7
7,22 ↔ 7.5
21,7 ↔ 7
21,21 ↔ 0
21,22 ↔ 0.5
22,7 ↔ 7.5
Therefore
- Mean of the sample MAD=3.3
- Population MAD =6.4
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1) The y- axis is where x = 0, so the line "y = -1/2x - 3" will cross the y-axis when x = 0. You plug in "x = 0" into the equation, and get y = 0 -3, so y = -3. That means the line " y = -1/2x - 3" will cross the y-axis ar (0, -3)
2) If there are 2 parallel lines, then there is no solution, because the definition of parallel lines is, " 2 lines in the same plane, that never meet." That makes the solution inconsistent.
Answer:
-5
Step-by-step explanation:
Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>
where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.
P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)
… = P(<em>Z</em> < 0.24)
… ≈ 0.5948
