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Reptile [31]
4 years ago
15

Mr. Patrick teaches math to 1515 students. He was grading tests and found that when he graded everyone's test except Payton's, t

he average grade for the class was 8080. After he graded Payton's test, the test average became 8181. What was Payton's score on the test?
Mathematics
1 answer:
julsineya [31]4 years ago
7 0
Given:
15 students
average grade: 80 for 14 students
average grade: 81 for 15 students

80 * 14 = 1120
81 * 15 = 1215

1215 - 1120 = 95

Payton's score on the test is 95.
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A line passes through the point (1,4) and is perpendicular to the line with equations y=-1/5x+2. what's the equation of the line
jekas [21]

To find the slope of the perpendicular line, you can take the negative reciprocal of the slope of the line it is perpendicular to.

Taking the negative reciprocal of -1/5 gives 5.

Now we have y=5x+b, where b is the y-intercept. Since we know that the perpendicular line passes through the point (1,4), we can substitute those values into the equation we have to find b.

y=5x+b

4=5(1)+b

4=5+b

b=-1

Therefore, the equation of the perpendicular line is y=5x-1.

4 0
3 years ago
Use the the factor theorem to determine wether the first polynomial is a factor of the second. X-3; 2x^2-4x+30
Firdavs [7]
Given the polynomial function 

P(x)=2 x^{2} -4x+30

If (x-3) is a factor of P(x), then

P(x)=2 x^{2} -4x+30=(x-3)*Q(x), for some polynomial Q of 1st degree,

Then according to the factor theorem P(3)=0, because P(3)=(3-3)Q(x)=0*Q(3)=0.

Check

P(3)=2 (3)^{2} -4(3)+30=18-12+30=36≠0


we see that P(3) is not 0, so (x-3) is not a factor of P(x).


Answer: no 
6 0
3 years ago
Simplify (3x22)*divided*6+[28-(4)^2]=<br><br> A. 23 <br> B. 55<br> C. 46 <br> D. 32
Dominik [7]
<span>Simplify (3x22)*divided*6+[28-(4)^2]=
</span>the answer is A 23     
7 0
4 years ago
Read 2 more answers
Please someone help me with this
Ivenika [448]

Answer:

See explanation

Step-by-step explanation:

Triangle ABC ahs vertices at points A(-4,-4), B(-1,-2) and C(-1,-4).

<u>1 way:</u> First reflect this triangle across the y-axis to form the triangle A''B''C'' which vertices are at points A''(4,-4), B''(1,-2) and C''(1,-4).

Then translate this triangle 7 units up to form the triangle A'B'C' with vertices:

A'(4,-4+7)=A'(4,3)\\ \\B'(1,-2+7)=B'(1,5)\\ \\C'(1,-4+7)=C'(1,3)

<u>2 way:</u> First translate this triangle 7 units up to form the triangle A''B''C'' which vertices are at points A''(-4,3), B''(-1,5) and C''(-1,3).

Then reflect this triangle across the y-axis to form the triangle A'B'C' with vertices:

A'(-(-4),3)=A'(4,3)\\ \\B'(-(-1),5)=B'(1,5)\\ \\C'(-(-1),3)=C'(1,3)

8 0
3 years ago
Can any kind soul help me ASAP!​
CaHeK987 [17]

Answer:

Hope it helps u

Step-by-step explanation:

As we know that ,

Mean = sum of the terms/ numbers of terms

But here grouped data is given so , we use the formula

Mean=∑[f. m]/ ∑f

where f is frequency and m is mid point of each height ,

Now first we have to find the mid point of each interval, where

midpoint of each interval = (lower boundary + upper boundary)/2

m1=(150+154)/2 = 152

m2=(155+159)/2= 157,now found other by same formula, for each interval

m3= 162

m4= 167

m5=172    Now we find the midpoint of each interval ,so now

∑[f. m]=f1*m1+f2*m2+f3*m3+f4*m4+f5*m5

now putting the values of each frequency for given interval and midpoint of each interval we will get,

∑[f. m]=456+942+1296+167*x+344 = 167*x+3038

Now find,

∑f=f1+f2+f3+f4+f5

∑f=19+x

Now we have,

∑[f. m]=167*x+3038

∑f=19+x

also given mean height=161.6 cm

putt these values in above equation we get,

161.6=\frac{167*x+3038}{19+x}

now solve this ,

161.6(19+x)=167*x+3038

3070.4+161.6*x=167*x+3038

3070.4-3038=167*x-161.6*x

32.4=5.4*x

x=32.4/5.4

<h2>x=6   Ans........</h2>

3 0
3 years ago
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