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Reptile [31]
4 years ago
15

Mr. Patrick teaches math to 1515 students. He was grading tests and found that when he graded everyone's test except Payton's, t

he average grade for the class was 8080. After he graded Payton's test, the test average became 8181. What was Payton's score on the test?
Mathematics
1 answer:
julsineya [31]4 years ago
7 0
Given:
15 students
average grade: 80 for 14 students
average grade: 81 for 15 students

80 * 14 = 1120
81 * 15 = 1215

1215 - 1120 = 95

Payton's score on the test is 95.
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Suppose an arrow is shot upward on the moon with a velocity of 44 m/s, then its height in meters after tt seconds is given by h(
andreev551 [17]

Answer:

a. 38.19m/s

b. 38.605m/s

c. 38.937m/s

d. 39.0117m/s

e. 39.01917m/s

Step-by-step explanation:

The average velocity is defined as the relationship between the displacement that a body made and the total time it took to perform it. Mathematically is given by the next formula:

v_a_v_g = \frac{\Delta x}{\Delta t} =\frac{x_f-x_i}{t_f-t_i}

Where:

x_f=Final\hspace{3}distance\hspace{3}traveled\\x_i=Initial\hspace{3}distance\hspace{3}traveled\\t_f=Final\hspace{3}time\hspace{3}interval\\t_i=Initial\hspace{3}time\hspace{3}interval

a. Let's find h(3) and h(4) using the data provided by the problem:

h(3)=44(3)-0.83(3^2)=124.53=x_i\\h(4)=44(4)-0.83(4^2)=162.72=x_f

The average velocity over the interval [3, 4] is :

v_a_v_g=\frac{162.72-124.53}{4-3} =38.19m/s

b. Let's find h(3.5) using the data provided by the problem:

h(3.5)=44(3.5)-0.83(3.5^2)=143.8325=x_f

The average velocity over the interval [3, 3.5] is :

v_a_v_g=\frac{143.8325-124.53}{3.5-3} =38.605m/s

c. Let's find h(3.1) using the data provided by the problem:

h(3.1)=44(3.1)-0.83(3.1^2)=128.4237=x_f

The average velocity over the interval [3, 3.1] is :

v_a_v_g=\frac{128.4237-124.53}{3.1-3} =38.937m/s

d. Let's find h(3.01) using the data provided by the problem:

h(3.1)=44(3.01)-0.83(3.01^2)=124.920117=x_f

The average velocity over the interval [3, 3.01] is :

v_a_v_g=\frac{124.920117-124.53}{3.01-3} =39.0117m/s

e. Let's find h(3.001) using the data provided by the problem:

h(3.001)=44(3.001)-0.83(3.001^2)=124.5690192=x_f

v_a_v_g=\frac{124.5690192-124.53}{3.001-3} =39.01917m/s

7 0
3 years ago
can someone help me with this i'm really confused heh... i'll give you a 5 star rating and brainliest answer!​
lutik1710 [3]
1. m= 4/9
2. m=4
3. m=-11
4. m=1/2
7 0
3 years ago
Sonya just turned 21 years old and will soon begin her junior year of college in
andrezito [222]

Answer:

A or D

Step-by-step explanation:

if not sorry:(

4 0
3 years ago
Read 2 more answers
Um negociante comprou 8 barricas de vinho todas com a mesma capacidade tendo pago R$7,00 o litro é vendido a R$9,00 ele ganhou a
Law Incorporation [45]

Answer:

each barrel has a capacity of 78,75  liters

Step-by-step explanation:

since the sold 8 barrels and assuming that each have the same capacity and are sold to the same price, the total amount he earned is

total earnings = number of barrels * number of liters/ barrel * earnings/liter

R$1,260,00 = 8 barrels * number of liters/ barrel * ( R$9,00- $7,00) /liter

number of liters/ barrel = R$1,260,00/(8 barrels*R$2,00 /liter ) = 78,75 liters/barrel

therefore each barrel has a capacity of 78,75  liters

5 0
3 years ago
(Giving brainliest to correct answer)<br><br> Congruence
MakcuM [25]

your answer is

B. sas

good luck :)

6 0
3 years ago
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