<h3>
Answer: 3x - 4y = 40</h3>
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Work Shown:
y = (3/4)x - 10
4y = 3x - 40 .... multiply everything by 4 to clear out the fraction
4y+40 = 3x
40 = 3x-4y
3x-4y = 40
This is in the form Ax+By = C
A = 3, B = -4, C = 40
This is not the only solution possible since we can multiply both sides by some number to scale the equation.
Answer:
so the answer is 50%
Step-by-step explanation:The interquartile range is the difference between the upper quartile and the lower quartile. In example 1, the IQR = Q3 – Q1 = 87 - 52 = 35. The IQR is a very useful measurement. It is useful because it is less influenced by extreme values as it limits the range to the middle 50% of the values.
Answer:
probability of selecting the square is 63.7% approximately
Step-by-step explanation:
First of all, the probability of the point of choice is within the red square can be obtained with this formula
probability = expected outcome / total number of possible outcomes
In this case, we are not dealing with discrete values which can be counted. instead, we are dealing with areas.
We are to go about this problem by finding the area of the internal square and dividing it by the area of the circle.
Area of the square
Area of the square = 
where length = 
Area = 
Area of the circle
Area of the circle = 
area of circle =
Probablity of selecting the square =
32/50.26 = 0.6366
To express this as a percentage, we multiply our answer by 100.
This will give us 0.6366 X 100 = 63.7% approximately
Solution:
<u>Note that:</u>
- Speed = Distance/Time
- Vaimiti speed = 1.1 m/s
- Jabril speed = 1.3 m/s
<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>
- Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
- => Vaimiti's time to reach school: 1500 seconds
<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>
- Jabril's time to reach school: 30 minutes = 30 x 60 seconds
- => Jabril's time to reach school: 1800 seconds
<u>Finding the distance of Vaimiti:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- => 1.1 meters/second = Distance/1500
- => 1.1 x 1500 = Distance
- => 1650 meters = Distance (In meters)
<u>Finding the distance of Jabril:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- 1.3 meters/second = Distance (In meters)/1800 seconds
- => 1.3 x 1800 = Distance (In meters)
- => 2340 meters = Distance (In meters)
This can lead to two possible solutions:
Possible solution #1:
<u>Finding the difference between the two distances:</u>
- 2340 meters - 1650 meters = Difference (In meters)
- => 690 meters
Possible solution #2:
The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.
Hoped this helped!
Answer:
3 and 5
Step-by-step explanation:
use the guess and check method form the numbers 1, 3, 5 since only the square of these 3 numbers are under 34.