Given: 120 & 360
Find:
Least
common multiple of 120 and 360
Solution:
In order to use the number patterns to find the least common
multiple of 120 and 360, we need to factor each value first and then, we choose
all the factors that appear in any of the column and then we multiply them.
<span>
<span><span>
<span>
120:
</span>
<span>
2
</span>
<span>
2
</span>
<span>
2
</span>
<span>
3
</span>
<span>
</span>
<span>
5
</span>
</span>
<span>
<span>
360:
</span>
<span>
2
</span>
<span>
2
</span>
<span>
2
</span>
<span>
3
</span>
<span>
3
</span>
<span>
5
</span>
</span>
<span>
<span>
LCM:
</span>
<span>
2
</span>
<span>
2
</span>
<span>
2
</span>
<span>
3
</span>
<span>
3
</span>
<span>
5
</span>
</span>
</span></span>
Therefore, the Least Common Multiple (LCM) of 120 and 360 is:
2 x 2 x 2 x 3 x 3 x 5 = 360
I think the answer is C and I’m sorry if u get it wrong
1. $85
2. $110
3.$135
4. $160
Explanation: $60 is a one time fee so only has to be used once in a formula.
Y:25x+60 X= the # of days so just multiply numbers of days by 25 then add the 60.
Answer:
The answer to your question is r = 4 in
Step-by-step explanation:
Data
Volume = 4000 π in³
height = 250 in
radius = ?
Process
1.- Look the formula to calculate the volume of a cylinder
Volume = πr²h
2.- Solve for r²
r² = Volume / πh
3.- Substitution
r² = 4000π / π(250)
4.- Simplification
r² = 16
r = √16
5.- Result
r = 4 in
Answer:
3m² + 2mn + 7n²
Step-by-step explanation:
Subtract m² + 3mn - n² from 4m² + 5mn + 6n², that is
4m² + 5mn + 6n² - (m² + 3mn - n²)
= 4m² + 5mn + 6n² - m² - 3mn + n² ← collect like terms
= 3m² + 2mn + 7n²