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Mekhanik [1.2K]

4 years ago

10

In Chad's reading class, all the students are reading the same book. The school bought each student a book at $7 per book. If th

ere are 27 students in Chad's class, which of the following expressions could not be used to calculate the total cost?
7(20) + 7(7), 7(30) - 7(3) 7(30) - 7(7)

1 answer:

Allushta [10]4 years ago

6 0

The last one 7(30)-7(7) because if you do it then it is 7(23) which doesn’t make sense because it is 27 we need to find

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3 years ago

At a carnival, 700 tickets were sold for a total

Diano4ka-milaya [45]

Answer:

The adult tickets are <u>400</u> and the children tickets are <u>300</u>.

Step-by-step explanation:

Given:

At a carnival, 700 tickets were sold for a total amount of $5500. An adult ticket cost $10 and a children's ticket cost $5.

Now, to find the number of adult tickets and the number of children's tickets sold.

<em>Let the number of adult tickets be </em> $x.$ <em />

<em>And let the number of children tickets be </em> $y.$ <em />

So, the total number of tickets sold:

$x+y=700\\\\y=700-x\ \ \ ....(1)$

Now, the total amount of tickets:

$x(10)+y(5)=5500$

Substituting the value of $y$ from equation (1):

$x(10)+(700-x)(5)=5500\\\\10x+3500-5x=5500\\\\5x+3500=5500$

<em>Subtracting both sides by 3500 we get:</em>

<em /> $5x=2000$ <em />

<em>Dividing boths sides by 5 we get:</em>

$x=400.$ <u />

<u>The number of adult tickets = 400.</u>

Now, substituting the value of $x$ in equation (1) we get:

$y=700-x\\\\y=700-400\\\\y=300.$

<u>The number of children tickets = 300.</u>

Therefore, the adult tickets are 400 and the children tickets are 300.

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<h2>1.</h2>

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2 years ago

Read 2 more answers

PLZ HELP WITH THIS QUESTION PLZ CORRECT ANSWERS!!! LOVE YOU THNX

iogann1982 [59]

Answer:

1) The value of x= 0.0642

2) $sin\theta=\frac{P}{H}=\frac{24}{25}$

$cos\theta=\frac{B}{H}=\frac{7}{25}$

$tan\theta=\frac{P}{B}=\frac{24}{7}$

$cosec\theta=\frac{H}{P}=\frac{25}{24}$

$cot\theta=\frac{B}{P}=\frac{7}{25}$

Step-by-step explanation:

1) Given : A right angle triangle with sides x and 10 and angle is 50°

To find : Value of x

Solution : Since, it is a right angle triangle

Therefore, we apply $cos\theta=\frac{B}{H}$

Where Base = x, Hypotenuse= 10, angle = 50°

$cos(50)=\frac{x}{10}$

$0.642=\frac{x}{10}$

$0.0642=x$

The value of x= 0.0642

2) Given : $sec\theta=\frac{25}{7}$

To find : Value of $sin\theta,cos\theta,tan\theta,cosec\theta,cot\theta$

Solution : We have given $sec\theta=\frac{25}{7}$

$sec\theta=\frac{H}{B}$

so, B= 7 , H=25

By Pythagoras theorem,

$H^2=P^2+B^2$

$25^2=P^2+7^2$

$625-49=P^2$

$\sqrt{576}=P^2$

$P=24$

Now, P=24, B=7, H=25

$sin\theta=\frac{P}{H}=\frac{24}{25}$

$cos\theta=\frac{B}{H}=\frac{7}{25}$

$tan\theta=\frac{P}{B}=\frac{24}{7}$

$cosec\theta=\frac{H}{P}=\frac{25}{24}$

$cot\theta=\frac{B}{P}=\frac{7}{25}$

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3 years ago