Answer:
Step-by-step explanation:
you have t as a total amount of the whole class.
f= did not pass and you place the total number next to it like this; f/t represents that group. You continue this in your workings.
f/t = probability failed.
p/t = probability passed
c/t = probability completed
dc/t = probability did not complete
and draw a tree.
The random would be either of these, we know there s a possibility of 1/4 but the odds stay central. We look for a new way after this data is converted as a fraction and show these fractions as your answer.
Answer:
-77
Step-by-step explanation:
give brainliest
Answer:
47
Step-by-step explanation:
Let a, b, and c be those three numbers.
When two of the three numbers are added at a time, the possible sums are 32, 39, 23. Let
Add these three equations:
Divide this equation by 2:
The sum of all three numbers is 47.
Answer:
1.) 6√13/13
2.) 4√13/13
3.) 3
Step-by-step explanation:
given that cot(x) = 2/3
But cot(x) = 1/tan(x)
Substitutes 1/tan(x) for cot(x)
1/tan(x) = 2/3
Reciprocate both sides
Tan(x) = 3/2 = opposite/adjacent
Use pythagorean theorem to find the hypothenus.
Hypothenus = sqrt ( 3^2 + 2^2 )
Hypothenus = sqrt ( 9 + 4 )
Hypothenus = sqrt (13)
Hypothenus = √13
1.) Sin(x) = opposite/hypothenus = 3/√13
Rationalise
3/√13 × √13/√13
3√13/13
Sin(2x) = 2 × 3√13/13
Sin(2x) = 6√13/13
2.) Cos( x ) = adjacent/hypothenus
Cos (x) = 2/√13
Rationalise
2/√13 × √13 /√13
2√13/13
Cos(2x) = 2 × 2√13/13
Cos(2x) = 4√13/13
3.) Tan (x) = 3/2
tan (2x) = 2 × 3/2
Tan(2x) = 3
