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Archy [21]
3 years ago
15

Please help I’ve been stuck on this for over 20 mins!

Mathematics
2 answers:
il63 [147K]3 years ago
7 0

Answer:

The quotient is 5 and 1/3

Step-by-step explanation:

  1. 2 ÷ 3/8 = 2/1 × 8/3
  2. \frac{2}{1} × \frac{8}{3} = \frac{16}{3}  
  3. \frac{16}{3} = 5\frac{1}{3}  

I hope this helps!

fgiga [73]3 years ago
5 0

Answer:

5 1/3

Step-by-step explanation:

2÷3/8=

2*8/3=5 1/3

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Children 4 years old or younger can ride the train for free. Write an inequality that expresses who can ride the train for free.
viktelen [127]

x<=4

x is less than or equal to four

children less than or equal to four can ride the train for free

3 0
3 years ago
A fair coin is tossed repeatedly. What is the probability that three heads in a row will occur before a tail followed by two hea
Masteriza [31]

The probability that you can get N heads in a row would be:

Let <span>p</span> be the probability of flipping a heads. Let <span>x</span> be number of flips needed to achieve <span>h </span>consecutive heads. The solution is <span><span>E(x) = (<span><span>1−<span>p^h) / (</span></span><span><span>p^h</span>(1−p))</span></span></span></span>

This expression may be derived as follows. The probability of being successful immediately is <span><span>p^r.</span></span> However, one might get a tails immediately. In that case, the number of flips needed is <span><span>1+E(x) </span></span>(one flip has been used and we are back to the original position). We might get a heads and then a tails. In this case two flips have been used and we are back to the original position. Continue this up to <span><span>h−1</span></span> heads followed by a tails in which case <span>h</span> flips have been used and we are back to the original position.

3 0
3 years ago
(6,-5) is a point on the terminal side of 0. Find the exact values of cos0, csc0, and tan0.
Dmitrij [34]

point (6, -5) => x = 6, y = -5

r =√6² +(-5)² = √(36+25)=√61

the exact value of :

cos 0 = x/r = 6/√61 = 6/61 √61

csc 0 = r/y = √61/(-5) = -1/5 √61

tan 0 = y/x = -5/6

4 0
2 years ago
Read 2 more answers
In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AC=5 and BH=2, find AH and CH.
Yakvenalex [24]

Answer:

  AH = 1 or 4

  CH = 4 or 1

Step-by-step explanation:

An altitude divides a right triangle into similar triangles. That means the sides are in proportion, so ...

  AH/BH = BH/CH

  AH·CH = BH²

The problem statement tells us AH + CH = AC = 5, so we can write

  AH·(5 -AH) = BH²

  AH·(5 -AH) = 2² = 4

This gives us the quadratic ...

  AH² -5AH +4 = 0 . . . . in standard form

  (AH -4)(AH -1) = 0 . . . . factored

This equation has solutions AH = 1 or 4, the values of AH that make the factors be zero. Then CH = 5-AH = 4 or 1.

3 0
3 years ago
Can someone please answer this question I need it today please show work and please answer it correctly i
svlad2 [7]

Answer:

24) $495

25) 14%

26) 25/X = 83/100

27) 0.7p

28) x + .085x and 1.085x

29) $221.90

30) $24.10

31) $6.13

32) 40%

Step-by-step explanation:

24) 600 - (600 × 0.25) = 450

450 × 1.10 = 495

25) (106 - 93) ÷ 93 = 0.13978

0.13978 × 100 = 13.978 ~ 14

27) 1.0 - 0.3 = 0.7

28) 1.00 + 0.085 = 1.085

29) 100% - 15% = 85%

240 × 0.85 = 204

204 × 1.0875 = 221.85

30) 25.89 × 4 = 103.56

103.56 + 179.99 = 283.55

283.55 × 0.085 = 24.10175

31) 8.75 × 0.70 = 6.125

32) 80 - (80 × 0.40) = 48

4 0
3 years ago
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