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Murljashka [212]

3 years ago

15

Write an algebraic expression for two fifths the cube of a number

1 answer:

pashok25 [27]3 years ago

7 0

N - the number

$\dfrac{2}{5}n^3$

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Please help <br> show all work <br> thank you

timama [110]

To start off, let's cross-multiply this proportion. We get the following:

$15a=8b$

Now, divide both sides by 8

$\frac{15a}{8}=b$

Now, divide both sides by 15

$\frac{a}{8}=\frac{b}{15}$

That's your answer. Hope this helps! :)

4 0

3 years ago

Equation that passes through the points (-1,0)(0,2)

Simora [160]

1. Find the slope.

2. Plug the slope you found in step 1, one of the given points, and plug both into the point-slope formula.

The point-slope formula is:

y - y_1 = m(x - x_1)

3. Solve the point-slope formula for y.

Your final answer must be in the form

y = mx + b

7 0

3 years ago

The sum of two numbers is equal to 11 and the difference is 19. What are the two numbers?

charle [14.2K]

$\bold{\huge{\pink{\underline{ Solution }}}}$

<u>We </u><u>have </u><u>given </u><u>in </u><u>the </u><u>question </u><u>that</u><u>, </u>

<u>The </u><u>sum </u><u>of </u><u>2</u><u> </u><u>numbers </u><u>is </u><u>equal </u><u>to </u><u>1</u><u>1</u><u> </u>
<u>The </u><u>difference </u><u>between </u><u>two </u><u>numbers </u><u>is </u><u>1</u><u>9</u><u> </u><u>.</u>

$\bold{\underline{ To \: Find }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y</u><u>. </u>

$\bold{\underline{ Let's \: Begin }}$

Let the two numbers be x and y

<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>

$\sf{ x + y = 11......eq(1) }$

$\sf{ x - y = 19......eq(2) }$

<u>Solving </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

$\sf{ x + y = 11 }$

$\sf{ x = 11 - y ......eq(3 ) }$

<u>Subsituting </u><u>eq(</u><u>3</u><u> </u><u>)</u><u> </u><u>in </u><u>eq</u><u>(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ x - y = 19 }$

$\sf{ ( 11 - y) - y = 19 }$

$\sf{ 11 - y - y = 19 }$

$\sf{ 11 - 2y = 19 }$

$\sf{ - 2y = 19 - 11 }$

$\sf{ - 2y = 8}$

$\sf{ y = 8/(-2) }$

$\sf{ y = - 4 }$

$\sf{\red{Thus ,\: the\: value\: of \: y = -4}}$

<u>Now</u><u>, </u><u> </u><u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>3</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ x = 11 - y }$

$\sf{ x = 11 - (-4 ) }$

$\sf{ x = 11 + 4 }$

$\sf{ x = 15 }$

Hence, The value of x and y are 15 and (-4) .

5 0

2 years ago

1/4c+5/3c-4=2-1/12 What dose c equal

Ivan

Answer:

c=71/23

Step-by-step explanation:

I think

8 0

3 years ago

ALGEBRA Find the value of each variable in the parallelogram.

Doss [256]

You didn’t include the parallelograms

3 0

3 years ago