Direct variation is y = kx, where k is the constant of variation.
But now it says y varies directly with x2 (or 2x), so now the x in the equation is 2x.
The equation is y = k(2x)
Now you find k.
y = 96 when x = 4.
(96) = k(2*4)
96 = k(8)
k = 12
The equation is now y = 12(2x)
To find the value of y when x=2, plug 2 into the equation you made.
y = 12(2*2)
y = 48
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Now it's with a "quadratic variation," which is the same thing except x is squared.
The equation is y = kx^2
But y varies directly with x2 (same thing as 2x), so now it's y = k(2x)^2.
Now you find k by substituting y and x values that were given.
y = 180 when x = 6
(180) = k(2*6)^2
180 = k(12)^2
180 = k(144)
k = 1.25
k, 1.25, is the constant of variation.
Answer:
b i think
Step-by-step explanation:
The statement is true.
Answer: Option 1.
<u>Explanation:</u>
An horizontal beam is constantly flat and has a consistent cross-segment. Notwithstanding normal shaft parameters, bar has the accompanying properties: Direction. A flat shaft might be situated either along the worldwide X-hub or worldwide Y-pivot.
A horizontal beam is used to hold a building up right and to give the support to the building. But the length of the horizontal beam differs in an inverse way between the supports.
A) 24
24 x 10
b)
103
103 x 10
C) 35
35 x 10
D) 73
73 x 10
E) 28
28 x 10
F) 41
41 x 10
Answer:
x^2+1/x^2
(x+1/x)^2 = x^2+1/x^2 +2
(5)^2 = x^2+1/x^2 + 2
25 = x^2+1/x^2 + 2
25-2 = x^2+1/x^2
23 = x^2+1/x^2
Step-by-step explanation:
