Can someone plz help me with this one problem plz!!!

Helllppp porfavor:,)

tatuchka [14]

Answer:

1. x = 67.5

2. x = 2.5

3. x = 35.2

4. x = 2.0

5. x = 17.0

Step-by-step explanation:

Question 1

The proportion is set up in the form x/9 = 15/2. Multiply both sides by two to get rid of the two in the denominator on the right side. After doing so, multiply by 9 on both sides to get rid of the 9 in the denominator on the left:

2x/9 = 15

2x = 9(15)

Next solve for x:

2x = 135

x = 67.5

Question 2

The proportion is set up in the form 20/8.7 = 5.8/x. Multiply both sides by the second denominator, x, and then both sides by the first, 8.7. This will leave you with the work below:

20x/8.7 = 5.8

20x = 8.7(5.8)

Next, solve for x:

20x = 50.46

x = 2.523

Round to the nearest tenth:

x = 2.5

Question 3

The proportion is set up in the form 5/16 = 11/x. Multiply both sides by the second denominator, x, and then both sides by the first, 16. This will leave you with the work below:

5x/16 = 11

5x = 11(16)

Next, solve for x:

5x = 176

x = 35.2

Question 4

The proportion is set up in the form x/0.06 = 17/0.5. Multiply both sides by the second denominator, 0.5, and then both sides by the first, 0.06. This will leave you with the work below:

0.5x/0.06 = 17

0.5x = 17(0.06)

Next, solve for x:

0.5x = 1.02

x = 2.04

Round to the nearest tenth:

x = 2.0

Question 5

The proportion is set up in the form 29/x = 75/44. Multiply both sides by the second denominator, 44, and then both sides by the first, x. This will leave you with the work below:

29(44)/x = 75

29(44) = 75x

Next, solve for x:

1276 = 75x

x = 17.0133

Round to the nearest tenth:

x = 17.0

7 0

3 years ago

This year benny is 12 years old and his mom is 48 years old. what percent of his mom's age is benny's age

Dennis_Churaev [7]

12 • 4 = 48

25% of his mom's age is benny's age

3 0

3 years ago

The circumference of a circle is 3pi in. What is the area of the circle?

Nezavi [6.7K]

Answer:

A = 2.25 pi in^2

Step-by-step explanation:

The circumference of a circle is 3pi

so d = 3

Area of circle = pi r^2

r = 3/2 = 1.5

A = (1.5)^2 pi

A = 2.25 pi in^2

3 0

3 years ago

Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7

Nutka1998 [239]

As a Bernoulli equation:

$x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6$

Let $z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}$ . The ODE becomes

$-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4$
$\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4$
$x^6z=-6\displaystyle\int x^4\,\mathrm dx$
$x^6z=-\dfrac65x^5+C$
$z=-\dfrac6{5x}+\dfrac C{x^6}$
$y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}$
$y=\dfrac1{\frac C{x^6}-\frac6{5x}}$
$y=\dfrac{5x^6}{C-6x^5}$

With $y(3)=6$ , we get

$6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2$

so the solution is

$y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}$

which is valid as long as the denominator is not zero, which is the case for all $x\neq\sqrt[5]{\dfrac{4131}{12}}$ .

8 0

3 years ago

Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculato

Mariulka [41]

The mean of the dataset is the average, while the median is the middle element.

The mean and the median of the given dataset is 98.2
The results support the common belief that the mean body temperature is 98.6F

The mean of the dataset is calculated using:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{99.2+ 99.2 +98.2+............+97.7}{48}$

$\bar x = \frac{4715}{48}$

$\bar x = 98.2$

The median position is:

$Median = \frac{1}{2}(n + 1)$

$Median = \frac{1}{2}(48 + 1)$

$Median = \frac{1}{2}(49)$

$Median = 24.5$

This means that the median is the average of the 24th and 25th element

Using the sorted dataset, we have:

$Median = \frac{1}{2}(98.2 + 98.2)$

$Median = 98.2$

Because the calculated mean and the common belief (98.6) are close, then we can conclude that the results support the common belief that the mean body temperature is 98.6F