Solve graph and write the solution to each inequality in interval notation <br> 1. |b+3|>7

Calculate the amount of paint needed to cover the following door:

love history [14]

Answer:

Step-by-step explanation:

The door is shape is a combination of a rectangle and a semicircle with a square window.

Area of the door = Area of rectangle + area of a semi circle

Area of a rectangle = Length * Width (LW)

area of a semicircle = πr²/2 where r is the radius of the semi circle.

Given the length of the rectangle = 2m and its width = 1m

Area of rectangle = 2*1 = 2m²

Given the radius of the semicircle = 1/2 m

Area of the semi circle = π(0.5)²/2

= 0.25π/2

= 0.785/2

Area of the semicircle= 0.3925m²

Area of the door = 2+0.3925

Area of the door = 2.3925m²

Since we are not to paint the window, we will subtract the area of the window from the total area.

Area of the window = area of a square = 0.2*0.2

= 0.04m²

Area to be painted = Area of door - Area of the square

Area to be painted = 2.3925m² - 0.04m²

Area to be painted = 2.3535m²

Note that there was no enough information for us to calculate the amount of paint needed but knowing the area of the part to be painted can guide us.

4 0

3 years ago

An old-fashioned bicycle has two differently sized wheels. The circumference of the front wheel is 9 feet larger than the circum

Lady_Fox [76]

So, the bicycle looks like the one in the picture below.

now, the circumference of the smaller wheel, will just be C = 2πr, with a radius of "r".

we also know that the large wheel has a circumference that is 9 feet larger than the small one, so, since the small one has a circumference of 2πr, then the large one will have a circumference of 2πr + 9.

after Thomas cycled for a while, the large did 500 revolutions, or times around, whilst the small one did 1400, since it's smaller. On that time, they covered however, the same amount of ground, since they're on the same bike.

The amount covered by the small one in 1400 cycles, is 1400(2πr), that's how much ground it covered.

The amount covered by the large one in 500 cycles, is 500(2πr + 9).

And we know that ground covered, is the same for both, therefore, we also know that 1400(2πr) = 500(2πr + 9).

$\bf \stackrel{small~wheel}{1400(2\pi r)}~~=~~\stackrel{large~wheel}{500(2\pi r+9)}\implies 14(2\pi r)=5(2\pi r+9)
\\\\\\
28\pi r=10\pi r+45\implies 18\pi r=45\implies r=\cfrac{45}{18\pi }
\\\\\\
\boxed{r=\cfrac{5}{2\pi }}$

so, how much ground did they cover anyway?

well, we could use either, since we know what the radius is, hmmmm let's use say the small wheel's circumference,

$\bf 1400(2\pi r)\implies 1400\left(\underline{2\pi }\cdot \cfrac{5}{\underline{2\pi }} \right)\implies 1400(5)\implies \stackrel{feet}{7000}$

8 0

3 years ago

Read 2 more answers

What is y=x-3 and what is x=4

jek_recluse [69]

Do you have a graph for this?

3 0

3 years ago

30 POINTS! Please answer and show work for both!

monitta

The recommended approach for such equations is to eliminate fractions first, by multiplying by the LCM of the denominators. You can simply simplify, then work them as a 2-step linear equation, doing your arithmetic with the fractions as they are.

a) (5x-1)/7 + (4x-3)/2 -(3-2x)/2 = 6 . . . . . given

... 2(5x -1) +7(4x -3) -7(3 -2x) = 84 . . . . . multiply by 14

... 10x -2 +28x -21 -21 +14x = 84 . . . . . . eliminate parentheses

... 52x -44 = 84 . . . . . . . . . . . . . . . . . . . . collect terms

... 52x = 128 . . . . . . . . . . . . . . . . . . . . . . . add 44

... x = 32/13 . . . . . . . . . . . . . . . . . . . . . . . . divide by 52 and simplify

b) (4x−3)/2 − (5−2x)/3 − (3x−4)/3 = 5 . . . given

... 2x -3/2 -5/3 +(2/3)x -x +4/3 = 5 . . . . . . .eliminate parentheses

... (5/3)x -11/6 = 5 . . . . . . . . . . . . . . . . . . . . simplify

... (5/3)x = 41/6 . . . . . . . . . . . . . . . . . . . . . . add 11/6

... x = (41/6)/(5/3) = 41/10 . . . . . . . . . . . . . .divide by the coefficient of x

_____

Using the first method, you're dealing with integers and you can do a lot of the math in your head. Using the second method, you're dealing with fractions and mixed numbers. A calculator can be helpful, especially if it handles arithmetic with fractions nicely, as many graphing calculators do.

6 0

3 years ago

A woman paid $28 per a dress. She bought 6 dresses. How much money did the woman spend on dresses?

Tju [1.3M]

Answer:

$168

Step-by-step explanation:

28x6

= 168

4 0

2 years ago

Read 2 more answers

Solve graph and write the solution to each inequality in interval notation 1. |b+3|>7